Write a C function to evaluate the series
sin(x) = x – x3/3! + x5/5! – x7/7! …
up to 10 terms.
Analyze Above Problem Statement
1. In above sine series, observe the first term, which is x. Which can be written as x1/1!.
i.e., x = x1/1!;
2. Check the exponent and the number used to divide the value of x in each series. 1 followed by 3 which is followed by 5 and so on. If you observe closely they’re all odd numbers. Adding 2 to 1 gives you 3. Adding 2 to 3 gives you 5. Adding 2 to 5 gives you 7 and so on ..
So the sine series becomes:
sin(x) = x1/1! – x3/3! + x5/5! – x7/7! + x9/9! – x11/11! + x13/13! – x15/15! + x17/17! – x19/19!
Now we have all 10 terms in the sine series.
3. Now observe the sign. First term in the series is positive. Second term is negative. Third term is positive. Again the forth term is negative. So we can conclude that, first term starts with positive and then it’s an alternative between negative and positive.
4. Next we need to find factorial of each number which divides x in each series. i.e., 1, 3, 5, 7, 9, 11, 13, 15, 17, 19. (10 odd numbers)
Related Read:
Basics of Pointers In C Programming Language
Function / Methods In C Programming Language
Very Important Note:
Any address preceded by a * (Indirection operator) will fetch the value present at that address.
Video Tutorial: C Program To Evaluate sin(x) = x – (x^3)/3! + (x^5)/5! + (x^7)/7! + ..
[youtube https://www.youtube.com/watch?v=WF1UUdoZX5Q]
Source Code: C Program To Evaluate sin(x) = x – (x^3)/3! + (x^5)/5! + (x^7)/7! + ..
#include<stdio.h>
#include<math.h>
double factorial(int);
void calc(float, float*);
int main()
{
int x;
float radian, result = 0;
printf("Enter value of x in degrees\n");
scanf("%d", &x);
radian = x * (3.14159 / 180.0); // Convert Degree To Radian
calc(radian, &result);
printf("Sin(%d) = %f\n", x, result);
return 0;
}
void calc(float num, float *res)
{
int count, n = 1, sign = 1;
for(count = 1; (n <= 10); count += 2)
{
*res += sign * ( pow(num, count) / factorial(count) );
n += 1;
sign *= -1;
}
}
double factorial(int num)
{
int count;
double sum = 1;
for(count = 1; count <= num; count++)
{
sum *= count;
}
return(sum);
}
Output 1:
Enter value of x is degrees
0
Sin(0) = 0.000000
Output 2:
Enter value of x is degrees
30
Sin(30) = 0.500000
Output 3:
Enter value of x is degrees
45
Sin(45) = 0.707106
Output 4:
Enter value of x is degrees
60
Sin(60) = 0.866025
Output 5:
Enter value of x is degrees
90
Sin(90) = 1.000000
Check above output with the value present in below chart. If you further evaluate the values present in below chart, it matches with the output of our program:
Compound Assignment Operator
We are using compound assignment operator in this program.
sum *= count; count += 2 *res += sign * ( pow(num, count) / factorial(count) ); n += 1; sign *= -1;
which is equal to writing:
sum = sum * count; count = count + 2; *res = *res + sign * ( pow(num, count) / factorial(count) ); n = n + 1; sign = sign * -1;
Usually many advanced developers use such shorthand notations while writing the programs. So we need to at least understand their code while going through it on their git repository or a simple source file.
Compound Assignment Operators in C
Logic To Evaluate sin(x) = x – (x^3)/3! + (x^5)/5! + (x^7)/7! + ..
User enters value of x in degrees. We convert it to radian value using the formula:
radian = x * (3.14159 / 180.0);
C Program To Convert Degree To Radian
We pass the value of radian and address of another floating point variable result to a function calc();
Inside calc() function
Inside calc() function we iterate the for loop 10 times, as we need to find 10 terms in the series(according to the problem statement). We initialize the value of count(loop counter variable) to 1. For each iteration of for loop we increment the value of count by 2. For 10 iterations count value changes as follows: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19.
Inside for loop we calculate each series one by one:
*res += sign * ( pow(num, count) / factorial(count) );
sign *= -1;
We initialize the value of variable sign to 1. And then we alternate the sign from positive to negative, and negative to positive for each iteration.
We are making use of pow() builtin method to find num to the power of count. pow() is present in math.h library file, so we include it in the header of our program.
Calculate Power of a Number using pow(): C Program
We also call a method called factorial() to find factorial of the value present in variable count.
Inside factorial() function
Inside factorial() function we calculate the factorial of the passed number.
Factorial of a number is the product of all the numbers preceding it. For example, Factorial of 6 is 720 (1 x 2 x 3 x 4 x 5 x 6 = 720). Denoted by 6! = 720;
C Program To Find Factorial of a Number using Function
In general, n objects can be arranged in n(n – 1)(n – 2) … (3)(2)(1) ways. This product is represented by the symbol n!, which is called n factorial. By convention, 0! = 1.
Very Important Note
In factorial() function, variable sum has a return type of double. That is because int(integer) type variable can only hold up to 4 bytes of data. Where as double type variable can hold up to 8 bytes. Ofcourse these memory allocations are machine dependent, however on any machine double type variable holds more bytes than int type. So we prefer using double here as we’ll be calculating factorial for bigger numbers i.e., from 1 to 19. Since we’ll be returning value of sum from the factorial() function, we need to have a return type of double for the factorial() function too.
1. 1! = 1.000000 2. 3! = 6.000000 3. 5! = 120.000000 4. 7! = 5040.000000 5. 9! = 362880.000000 6. 11! = 39916800.000000 7. 13! = 6227020800.000000 8. 15! = 1307674368000.000000 9. 17! = 355687428096000.000000 10. 19! = 121645100408832000.000000
Using sizeof() operator we can know the memory allocation for each data type: Sizeof Operator in C Programming Language.
Also note that the format specifier for double data type is %lf.
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