C Program To Find Factorial of a Number using Function

Write a function to calculate the factorial value of any integer entered through the keyboard.

Related Read:
C Program To Find Factorial of a Number

Factorial of a number is the product of all the numbers preceding it. For example, Factorial of 6 is 720 (1 x 2 x 3 x 4 x 5 x 6 = 720).

In general, n objects can be arranged in n(n – 1)(n – 2) … (3)(2)(1) ways. This product is represented by the symbol n!, which is called n factorial. By convention, 0! = 1.

Video Tutorial: C Program To Find Factorial of a Number using Function


[youtube https://www.youtube.com/watch?v=OcXCoX51Xx4]

YouTube Link: https://www.youtube.com/watch?v=OcXCoX51Xx4 [Watch the Video In Full Screen.]


Source Code: C Program To Find Factorial of a Number using Function

#include<stdio.h>

void factorial(int);

int main()
{
    int num;

    printf("Enter a positive number to find Factorial\n");
    scanf("%d", &num);

    factorial(num);

    return 0;
}

void factorial(int num)
{
    int count, fact = 1;

    if(num == 0)
    {
        printf("Factorial of 0 is 1 (!0 = 1)\n");
    }
    else
    {
        for(count = 1; count <= num; count++)
        {
            fact = fact * count;
        }

        printf("\nFactorial of %d is %d (!%d = %d)\n", num, fact, num, fact);
    }
}

Output 1:
Enter a positive number to find Factorial
5

Factorial of 5 is 120 (!5 = 120)

Output 2:
Enter a positive number to find Factorial
4

Factorial of 4 is 24 (!4 = 24)

Output 3:
Enter a positive number to find Factorial
6

Factorial of 6 is 720 (!6 = 720)

Output 4:
Enter a positive number to find Factorial
7

Factorial of 7 is 5040 (!7 = 5040)

Output 5:
Enter a positive number to find Factorial
8

Factorial of 8 is 40320 (!8 = 40320)

Logic To Find Factorial of a Number

Complete for loop logic to find Factorial of a number is present at C Program To Find Factorial of a Number. Watch the video without fail to understand the logic.

Note: Function factorial doesn’t return anything so its return type is void. It accepts 1 integer type argument.

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C Program To Generate Fibonacci Series using Function

Lets write a C program to generate Fibonacci Series using function / method.

Related Read:
Fibonacci Series using While loop: C Program
C Program To Generate Fibonacci Series using For Loop

What Is Fibonacci Series ?
Fibonacci Series is a series of numbers where the first two Fibonacci numbers are 0 and 1, and each subsequent number is the sum of the previous two. Its recurrence relation is given by Fn = Fn-1 + Fn-2.

Below are a series of Fibonacci numbers(10 numbers):
0
1
1
2
3
5
8
13
21
34

How Its Formed:
0 <– First Number (n1)
1 <– Second Number (n2)
1 <– = 1 + 0 (previous two numbers)
2 <– = 1 + 1 (previous two numbers)
3 <– = 2 + 1 (previous two numbers)
5 <– = 3 + 2 (previous two numbers)
8 <– = 5 + 3 (previous two numbers)
13 <– = 8 + 5 (previous two numbers)
21 <– = 13 + 8 (previous two numbers)
34 <– = 21 + 13 (previous two numbers)

Video Tutorial: C Program To Generate Fibonacci Series using Function


[youtube https://www.youtube.com/watch?v=R3MPbqvYooA]

YouTube Link: https://www.youtube.com/watch?v=R3MPbqvYooA [Watch the Video In Full Screen.]


Source Code: C Program To Generate Fibonacci Series using Function

#include<stdio.h>

void fibonacci(int);

int main()
{
    int limit;

    printf("Enter the number of terms to be printed\n");
    scanf("%d", &limit);

    fibonacci(limit);

    return 0;
}

void fibonacci(int num)
{
    int n1 = 0, n2 = 1, n3, count;

    printf("\nFibonacci Series ..\n");
    printf("1. %d\n2. %d\n", n1, n2);

    for(count = 3; count <= num; count++)
    {
        n3 = n1 + n2;
        printf("%d. %d\n", count, n3);

        n1 = n2;
        n2 = n3;
    }
}

Output 1:
Enter the number of terms to be printed
5

Fibonacci Series ..
1. 0
2. 1
3. 1
4. 2
5. 3

Output 2:
Enter the number of terms to be printed
14

Fibonacci Series ..
1. 0
2. 1
3. 1
4. 2
5. 3
6. 5
7. 8
8. 13
9. 21
10. 34
11. 55
12. 89
13. 144
14. 233

Logic To Generate Fibonacci Series using Function

We ask the user to enter the limit i.e., how many terms in the Fibonacci series to be printed. We pass this user entered limit to function fibonacci.

Inside fibonacci function
We initialize n1 to 0 and n2 to 1 and display it to the console. We do this because we know that in any Fibonacci series the first two numbers are 0 and 1.

Now we add n1 and n2 and assign it to n3, and display the value of n3 – which is the next number in the Fibonacci series. We use for loop to keep printing the Fibonacci series until the limit entered by the user.

Note: Function fibonacci takes 1 integer type argument and doesn’t return anything, so its return type is void.

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C Program To Find Armstrong Numbers Between Range using Function

In today’s video tutorial lets find all the Armstrong numbers or Narcissistic numbers between user entered range, using function / method.

An Armstrong number or Narcissistic number is an n-digit base b number such that the sum of its (base b) digits raised to the power n is the number itself.

Example 1:
If number = 370
It has 3 digits: 3, 7 and 0. So n = 3.
result = 33 + 73 + 03 = 27 + 343 + 0 = 370.
So the original number 370 is equal to the result. So it’s an Armstrong Number.

Example 2:
If number = 8208
It has 4 digits: 8, 2, 0 and 8. So n = 4.
result = 84 + 24 + 04 + 84 = ‭4096‬ + 16 + 0 + ‭4096‬ = 8208.
So the original number 8208 is equal to the result. So it’s an Armstrong Number.

Related Read:
Swap 2 Numbers Using a Temporary Variable: C
Function / Methods In C Programming Language
C Program to Check Armstrong Number
C Program to print Armstrong Numbers Between Two Integers

Video Tutorial: C Program To Find Armstrong Numbers Between Range using Function


[youtube https://www.youtube.com/watch?v=nsVcZxEvIc8]

YouTube Link: https://www.youtube.com/watch?v=nsVcZxEvIc8 [Watch the Video In Full Screen.]


To count number of digits in a number

    int n = 0, temp;

    temp = num;

    while(temp)
    {
        temp = temp / 10;
        n++;
    }

To Iterate through the digits in the number

        while(num)
        {
            rem = num % 10;
            sum = sum + pow(rem, n);
            num = num / 10;
        }

To know above code logic, please visit and watch the video tutorial present at C Program to Check Armstrong Number.

Full Source Code: C Program To Find Armstrong Numbers Between Range using Function

#include<stdio.h>
#include<math.h>

float armstrong(int);

int main()
{
    int count, start, end, temp;

    printf("Enter start and end values\n");
    scanf("%d%d", &start, &end);

    if(start > end)
    {
        temp = start;
        start= end;
        end  = temp;
    }

    printf("Armstrong numbers between %d and %d are\n", start, end);

    for(count = start; count <= end; count++)
    {
        if(count == armstrong(count))
        {
            printf("%d is an Armstrong number\n", count);
        }
    }

    return 0;
}

float armstrong(int num)
{
    int rem, n = 0, temp;
    float sum = 0.0;

    temp = num;

    while(temp)
    {
        temp = temp / 10;
        n++;
    }

    while(num)
    {
        rem = num % 10;
        sum = sum + pow(rem, n);
        num = num / 10;
    }

    return(sum);
}

Output 1:
Enter start and end values
1
999
Armstrong numbers between 1 and 999 are
1 is an Armstrong number
2 is an Armstrong number
3 is an Armstrong number
4 is an Armstrong number
5 is an Armstrong number
6 is an Armstrong number
7 is an Armstrong number
8 is an Armstrong number
9 is an Armstrong number
153 is an Armstrong number
370 is an Armstrong number
371 is an Armstrong number
407 is an Armstrong number

Output 2:
Enter start and end values
500
99999
Armstrong numbers between 500 and 99999 are
1634 is an Armstrong number
8208 is an Armstrong number
9474 is an Armstrong number
54748 is an Armstrong number
92727 is an Armstrong number
93084 is an Armstrong number

Output 3:
Enter start and end values
1
99999
Armstrong numbers between 1 and 99999 are
1 is an Armstrong number
2 is an Armstrong number
3 is an Armstrong number
4 is an Armstrong number
5 is an Armstrong number
6 is an Armstrong number
7 is an Armstrong number
8 is an Armstrong number
9 is an Armstrong number
153 is an Armstrong number
370 is an Armstrong number
371 is an Armstrong number
407 is an Armstrong number
1634 is an Armstrong number
8208 is an Armstrong number
9474 is an Armstrong number
54748 is an Armstrong number
92727 is an Armstrong number
93084 is an Armstrong number

Output 4:
Enter start and end values
1
500
Armstrong numbers between 1 and 500 are
1 is an Armstrong number
2 is an Armstrong number
3 is an Armstrong number
4 is an Armstrong number
5 is an Armstrong number
6 is an Armstrong number
7 is an Armstrong number
8 is an Armstrong number
9 is an Armstrong number
153 is an Armstrong number
370 is an Armstrong number
371 is an Armstrong number
407 is an Armstrong number

Logic To Find Armstrong Numbers Between Range using Function

We ask the user to enter start and end value i.e., the range. Using for loop we iterate through all the numbers between start and end. For each iteration of for loop, variable count holds the number which we need to check if its Armstrong number or not.

Value of count is passed to function armstrong. Function armstrong counts the number of digits present in the integer number(we store it inside variable n) and then multiplies all the individual digits of the number by n and adds them. The sum is returned back to the calling function.

If value present in count and the value returned by armstrong method are equal, then the value present in count is an Armstrong number and will be displayed on the console window.

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C Program To Find Armstrong Numbers Between 1 and 500 using Function

Lets write a C program to find Armstrong number or Narcissistic number from 1 to 500 using function.

Problem Statement
Write a C program to print out all Armstrong numbers or Narcissistic number between 1 and 500. If sum of cubes of each digit of the number is equal to the number itself, then the number is called an Armstrong number. Hint: Use function / method.

An Armstrong number or Narcissistic number is an n-digit base b number such that the sum of its (base b) digits raised to the power n is the number itself.

Example 1:
If number = 153
It has 3 digits: 1, 5 and 3. So n = 3.
result = 13 + 53 + 33 = 1 + 125 + 27 = 153.
So the original number 153 is equal to the result. So it’s an Armstrong Number.

Example 2:
If number = 1634
It has 4 digits: 1, 6, 3 and 4. So n = 4.
result = 14 + 64 + 34 + 44 = 1 + 1296 + 81 + 256 = 1634.
So the original number 1634 is equal to the result. So it’s an Armstrong Number.

Related Read:
C Program to print Armstrong Numbers between 1 and 500

Video Tutorial: C Program To Find Armstrong Numbers From 1 To 500 using Function


[youtube https://www.youtube.com/watch?v=V0Ws8aS4GwI]

YouTube Link: https://www.youtube.com/watch?v=V0Ws8aS4GwI [Watch the Video In Full Screen.]


To count the digits in a number

    int n = 0, temp;

    temp = num;

    while(temp)
    {
        temp = temp / 10;
        n++;
    }

To Iterate through the digits in the number

    while(num)
    {
        rem = num % 10;
        sum = sum + pow(rem, n);
        num = num / 10;
    }

To know above code logic, please visit and watch the video tutorial present at C Program to Check Armstrong Number.

Full Source Code: C Program To Find Armstrong Numbers Between 1 and 500 using Function

#include<stdio.h>
#include<math.h>

float armstrong(int);

int main()
{
    int count;

    for(count = 1; count <= 500; count++)
    {
        if(count == armstrong(count))
        {
            printf("%d is a Armstrong number\n", count);
        }
    }

    return 0;
}

float armstrong(int num)
{
    int rem, n = 0, temp;
    float sum = 0.0;

    temp = num;

    while(temp)
    {
        temp = temp / 10;
        n++;
    }

    while(num)
    {
        rem = num % 10;
        sum = sum + pow(rem, n);
        num = num / 10;
    }

    return(sum);
}

Output:
1 is a Armstrong number
2 is a Armstrong number
3 is a Armstrong number
4 is a Armstrong number
5 is a Armstrong number
6 is a Armstrong number
7 is a Armstrong number
8 is a Armstrong number
9 is a Armstrong number
153 is a Armstrong number
370 is a Armstrong number
371 is a Armstrong number
407 is a Armstrong number

#include<stdio.h>
#include<math.h>

float armstrong(int);

int main()
{
    int count;

    for(count = 1; count <= 500; count++)
    {
        if(count == armstrong(count))
        {
            printf("%d is a Armstrong number\n", count);
        }
    }

    return 0;
}

float armstrong(int num)
{
    int rem;
    float sum = 0.0;

    while(num)
    {
        rem = num % 10;
        sum = sum + (rem * rem * rem);
        num = num / 10;
    }

    return(sum);
}

Output:
1 is a Armstrong number
153 is a Armstrong number
370 is a Armstrong number
371 is a Armstrong number
407 is a Armstrong number

Logic To Find Armstrong Numbers Between 1 and 500 using Function

Using for loop(inside main method) we pass value(from 1 to 500) to armstrong function one by one. The value is present in variable count.

Function armstrong checks the number of digits present in the number(we call it as n) and then separates individual digits of the number and multiplies all the individual digits n times and adds them all and finally returns the sum.

If the armstrong function returned number and the value present in count are same then the value present in count is an Armstrong number, else we pass on to check the next number selected by for loop.

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C Program To Find Biggest of Three Numbers using Function

In this video tutorial you’ll learn how to find biggest of three integer numbers using function.

Related Read:
Nested if else Statement In C
Biggest of 3 Numbers: C
Biggest of 3 Numbers Using Ternary Operator: C

Video Tutorial: C Program To Find Biggest of Three Numbers using Function


[youtube https://www.youtube.com/watch?v=0fxG98WizAo]

YouTube Link: https://www.youtube.com/watch?v=0fxG98WizAo [Watch the Video In Full Screen.]

Source Code: C Program To Find Biggest of Three Numbers using Function

#include<stdio.h>

int biggest(int, int, int); // function prototype

int main()
{
    int a, b, c;

    printf("Enter 3 integer numbers\n");
    scanf("%d%d%d", &a, &b, &c);

    //function call biggest(a, b, c)
    printf("Biggest of %d, %d and %d is %d\n", a, b, c, biggest(a, b, c));

    return 0;
}

// function definition
int biggest(int x, int y, int z)
{
    if(x > y && x > z)
    {
       return x;
    }
    else
    {
       if(y > z)
          return y;
       else
          return z;
    }
}

Output
Enter 3 integer numbers
50
40
60
Biggest of 50, 40 and 60 is 60

Source Code: C Program To Find Biggest of Three Numbers using Function, Using Ternary Operator

#include<stdio.h>

int biggest(int, int, int); // function prototype

int main()
{
    int a, b, c;

    printf("Enter 3 integer numbers\n");
    scanf("%d%d%d", &a, &b, &c);

    //function call biggest(a, b, c)
    printf("Biggest of %d, %d and %d is %d\n", a, b, c, biggest(a, b, c));

    return 0;
}

// function definition
int biggest(int x, int y, int z)
{
   return( (x>y && x>z)?x:(y>z)?y:z );
}

Logic To Find Biggest of 3 Numbers using Function

We ask the user to enter 3 integer numbers. We pass those 3 integer numbers to user defined function biggest. Inside function biggest we use ternary operator to determine the biggest of those 3 numbers. Function biggest returns the biggest of the 3 numbers back to the calling method/function – in above progam its main() method.

Note: Function biggest returns integer type data. And it takes 3 arguments of type integer. We’re calling function biggest from inside printf() function.

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