Lets write a C program to enter number till the user wants. At the end it should display the count of positive number, negative number and zeros entered, using Ternary Operator or Conditional Operator and without using arrays.
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while loop in C programming
Positive or Negative or Zero Using Ternary Operator: C Program
Note:
Any number greater than 0 is positive.
Any number less than 0 is negative.
Expected Output for the Input
User Input:
Enter the limit
6
Enter 6 numbers
-1
0
2
-3
5
6
Output:
Positive Numbers: 3
Negative Numbers: 2
Number of zero: 1
Logic To Count Positive, Negative and Zero using Ternary Operator and without using Array
Complete logic to this program is present at C Program To Count Positive, Negative and Zero without using Array
Video Tutorial: C Program To Count Positive, Negative and Zero using Ternary Operator and without using Array
[youtube https://www.youtube.com/watch?v=OMGSxVCav24]
Source Code: C Program to Count Positive, Negative and Zero using Ternary Operator and without using Array
#include < stdio.h >
int main()
{
int limit, num, positive = 0, negative = 0, zero = 0;
printf("Enter the limit\n");
scanf("%d", &limit);
printf("Enter %d numbers\n", limit);
while(limit)
{
scanf("%d", &num);
(num > 0) ? positive++ : ((num < 0) ? negative++ : zero ++);
limit--;
}
printf("\nPositive Numbers: %d\n", positive);
printf("Negative Numbers: %d\n", negative);
printf("Number of zero: %d\n", zero);
return 0;
}
Output:
Enter the limit
5
Enter 5 numbers
2
-1
5
6
0
Positive Numbers: 3
Negative Numbers: 1
Number of zero: 1
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