multiplication

Assignment Operators in C

In this video tutorial we show Compound Assignment Operators in C programming language.

Related Read:
Simple Calculator Application In C

Assignment Operators

If a and c are the operands.

c += a; is equal to writing c = c + a;
c -= a; is equal to writing c = c – a;
c *= a; is equal to writing c = c * a;
c /= a; is equal to writing c = c / a;
c %= a; is equal to writing c = c % a;

Assignment Operator +=

 
#include < stdio.h >

int main()
{
    int a = 20, c = 30;

    c += a ; // c = c + a;

    printf("%d\n\n", c);

    return 0;
}

Output:
50

Assignment Operator -=

 
#include < stdio.h >

int main()
{
    int a = 20, c = 30;

    c -= a ; // c = c - a;

    printf("%d\n\n", c);

    return 0;
}

Output:
10

Assignment Operator *=

 
#include < stdio.h >

int main()
{
    int a = 20, c = 30;

    c *= a ; // c = c * a;

    printf("%d\n\n", c);

    return 0;
}

Output:
600

Assignment Operator /=

 
#include < stdio.h >

int main()
{
    int a = 2, c = 20;

    c /= a ; // c = c / a;

    printf("%d\n\n", c);

    return 0;
}

Output:
10

Assignment Operator %=

 
#include < stdio.h >

int main()
{
    int a = 2, c = 20;

    c %= a ; // c = c % a;

    printf("%d\n\n", c);

    return 0;
}

Output:
0

Compound Assignment Operators in C Programming Language

[youtube https://www.youtube.com/watch?v=-_ZBdT2Yxqo]

YouTube Link: https://www.youtube.com/watch?v=-_ZBdT2Yxqo [Watch the Video In Full Screen.]

You can also learn about Logical and Relational Operators in C:
Relational Operators In C
Logical Operators In C

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

Simple Calculator Program using Switch Case: C

In this video tutorial we shall perform Addition, Subtraction, Multiplication and Division of numbers based on user input, using switch case statement(decision control statement).

We had written same calculator program using else-if clause. Same program has been modified to use Switch case in this program.
Simple Calculator Application In C

Simple Calculator using Switch Case: C Program

[youtube https://www.youtube.com/watch?v=HHuaYKKoMR4]

YouTube Link: https://www.youtube.com/watch?v=HHuaYKKoMR4 [Watch the Video In Full Screen.]

Working of Calculator Program
We display list of operation one can perform. That is,

1. Addition
2. Subtraction
3. Multiplication
4. Division

We ask the user to input his / her choice for arithmetic operation. If the user selects 1, then we ask the user to enter 2 integer numbers to perform addition operation. Once the user enters 2 integer numbers we add and display the result on the screen.

If the user enters wrong choice, we ask the user to enter proper choice.

Calculator Program using Switch Case: C Program

#include < stdio.h >

int main()
{
    int a, b;
    char choice;

    printf("Enter your choice\n");
    printf("a. Addition\nb. Subtraction\nc. Multiplication\nd. Division\n");
    scanf("%c", &choice);


   printf("Enter 2 integer numbers\n");
   scanf("%d %d", &a, &b);


    switch(choice)
    {
        case 'a': printf("%d + %d = %d\n", a, b, (a+b));
                break;

        case 'b': printf("%d - %d = %d\n", a, b, (a-b));
                break;

        case 'c': printf("%d x %d = %d\n", a, b, (a*b));
                break;

        case 'd': if( b != 0)
                    printf("%d / %d = %d\n", a, b, (a/b));
                else
                    printf("Number can't be divided by 0\n");
                break;

        default: printf("You entered wrong choice\n");
                 break;
    }

    return 0;
}

Output
Enter your choice
a. Addition
b. Subtraction
c. Multiplication
d. Division
c
Enter 2 integer numbers
5
10
5 x 10 = 50

In above program we are asking user to enter character a or b or c or d to perform addition, subtraction, multiplication and division operations respectively.

#include < stdio.h >

int main()
{
    int a, b, choice;

    printf("Enter your choice\n");
    printf("1. Addition\n2. Subtraction\n3. Multiplication\n4. Division\n");
    scanf("%d", &choice);

    if( choice > 4 )
    {
        printf("Select with in the range!\n");
    }
    else
    {
        printf("Enter 2 integer numbers\n");
        scanf("%d %d", &a, &b);
    }


    switch(choice)
    {
        case 1: printf("%d + %d = %d\n", a, b, (a+b));
                break;

        case 2: printf("%d - %d = %d\n", a, b, (a-b));
                break;

        case 3: printf("%d x %d = %d\n", a, b, (a*b));
                break;

        case 4: if( b != 0)
                    printf("%d / %d = %d\n", a, b, (a/b));
                else
                    printf("Number can't be divided by 0\n");
                break;

        default: printf("You entered wrong choice\n");
                 break;
    }

    return 0;
}

Output:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division
4
Enter 2 integer numbers
10
2
10 / 2 = 5

Here we are asking user to enter 1 or 2 or 3 or 4 to choose the arithmetic operation.

#include

int main()
{
    int a, b;
    char choice;

    printf("Enter your choice\n");
    printf("1. Addition\n2. Subtraction\n3. Multiplication\n4. Division\n");
    scanf("%c", &choice);

    printf("Enter 2 integer numbers. Format: a + b\n");
    scanf("%d %c %d", &a, &choice, &b);



    switch(choice)
    {
        case '+': printf("%d + %d = %d\n", a, b, (a+b));
                break;

        case '-': printf("%d - %d = %d\n", a, b, (a-b));
                break;

        case '*': printf("%d x %d = %d\n", a, b, (a*b));
                break;

        case '/': if( b != 0)
                    printf("%d / %d = %d\n", a, b, (a/b));
                else
                    printf("Number can't be divided by 0\n");
                break;

        default: printf("You entered wrong choice\n");
                 break;
    }

    return 0;
}

Output:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division
1
Enter 2 integer numbers. Format: a + b
50 + 60
50 + 60 = 110

Here we ask the user to enter values as well as the operation to be performed. Operands and operator.

Note 1: There is no need of curly braces inside case.
Note 2: If a case doesn’t end with break statement, then the execution continues and the block of code present inside next case will also get executed.
Note 3: default case is optional. And the code inside it executes only when non of the cases match.
Note 4: Here switch, case, break, default are all keywords / reserve words.

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

Simple Calculator Application In C

In this video tutorial we shall perform Addition, Subtraction, Multiplication and Division of numbers based on user input.

Simple Calculator Program In C

[youtube https://www.youtube.com/watch?v=QO6pCvM3xSQ]

YouTube Link: https://www.youtube.com/watch?v=QO6pCvM3xSQ [Watch the Video In Full Screen.]

Working of Calculator Program
We display list of operation one can perform. That is,

1. Addition
2. Subtraction
3. Multiplication
4. Division

If the user enters wrong choice, we ask the user to enter proper choice.

Student Grade Calculation using else-if clause

 
#include < stdio.h >

int main()
{
    int a, b, choice;

    printf("Enter your choice\n");
    printf("1. Addition\n2. Subtraction\n3. Multiplication\n4. Division\n\n");
    scanf("%d", &choice);

    if(choice > 4)
    {
        printf("You entered wrong choice\n");
    }
    else
    {
        printf("Enter 2 integer numbers\n");
        scanf("%d %d", &a, &b);
    }


    if(choice == 1)
    {
        printf("Addition of %d and %d is %d\n", a, b, (a+b));
    }
    else if(choice == 2)
    {
        printf("Subtraction of %d and %d is %d\n", a, b, (a-b));
    }
    else if(choice == 3)
    {
        printf("Multiplication of %d and %d is %d\n", a, b, (a*b));
    }
    else if(choice == 4)
    {
        if(b != 0)
            printf("Division of %d and %d is %d\n", a, b, (a/b));
        else
            printf("Number can not be divided by 0\n");
    }
    else
    {
        printf("Please enter any of these no 1, 2, 3, 4\n");
    }


    return 0;
}

Output 1:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

1
Enter 2 integer numbers
3
2
Addition of 3 and 2 is 5

Output 2:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

2
Enter 2 integer numbers
8
3
Subtraction of 8 and 3 is 5

Output 3:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

3
Enter 2 integer numbers
5
5
Multiplication of 5 and 5 is 25

Output 4:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

4
Enter 2 integer numbers
10
2
Division of 10 and 2 is 5

Output 5:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

4
Enter 2 integer numbers
0
12
Division of 0 and 12 is 0

Output 6:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

4
Enter 2 integer numbers
10
0
Number can not be divided by 0

Output 7:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

50
You entered wrong choice
Please enter any of these no 1, 2, 3, 4

Note: In division section(that is, choice 4) you can see nesting of if else statement. You can know more about nested if-else statements in this program: Nested if else Statement In C

Note: We can write the same program within while loop and ask the user if he wants to continue working inside calculator application. This avoids the need to exit and re-run the program. We’ll publish the code and video tutorial for the same in coming days. Stay subscribed to our YouTube Channel and blog.

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

Multiplication of 2 Numbers: C

In this video tutorial you can learn the procedure followed in C programming to multiply two numbers.

Related Read:

 
#include < stdio.h >

int main()
{
    int a, b, c;

    printf("Enter 2 numbers for multiplication\n");
    scanf("%d %d", &a, &b);

    c = a * b;

    printf("Multiplication of %d and %d is %d\n", a, b, c);

    return 0;
}

Output:
Enter 2 numbers for multiplication
25
5
Multiplication of 25 and 5 is 125

You can write same program without using third variable to calculate multiplication of 2 numbers, as below:

 
#include < stdio.h >

int main()
{
    int a, b;

    printf("Enter 2 numbers for multiplication\n");
    scanf("%d %d", &a, &b);

    printf("Multiplication of %d and %d is %d\n", a, b, (a*b));

    return 0;
}

Output:
Enter 2 numbers for multiplication
25
5
Multiplication of 25 and 5 is 125

Note: Instead of int you can take float variables too. That would help in taking both integer as well as real values from the user as input.

Scanf(): For user input

In above c program we are asking user to enter the values for variable a and b. You can know more about scanf() method/function in this video tutorial: Using Scanf in C Program

Multiplication of Two Numbers: C Programming

[youtube https://www.youtube.com/watch?v=AFbtnOAH7eE]

YouTube Link: https://www.youtube.com/watch?v=AFbtnOAH7eE [Watch the Video In Full Screen.]

This video was produced as building block for our simple calculator application.

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

Swap 2 numbers using Multiplication and Division: C

In this video tutorial we shall learn how to swap two integer numbers without using a temporary variable and by simply making use of multiplication and division.

 
#include < stdio.h >

int main()
{
    int a, b;

    printf("Enter 2 integer numbers\n");
    scanf("%d %d", &a, &b);

    printf("You entered a = %d and b = %d\n", a, b);

    a = a * b;
    b = a / b;
    a = a / b;

    printf("After swapping a = %d and b = %d\n", a ,b);

    return 0;
}

Output:
Enter 2 integer numbers
3
5
You entered a = 3 and b = 5
After swapping a = 5 and b = 3

Scanf(): For user input

In above c program we are asking user to enter the values for variable a and b. You can know more about scanf() method/function in this video tutorial: Using Scanf in C Program

Swap 2 numbers using only Multiplication and Division: C

[youtube https://www.youtube.com/watch?v=AcMEvVD0D4U]

YouTube Link: https://www.youtube.com/watch?v=AcMEvVD0D4U [Watch the Video In Full Screen.]

Swapping 2 Numbers In C using only Multiplication and Division: Logic

In our above program we are asking user to enter integer value for a and b.
If the user enters 10 and 5 for a and b respectively. Then our program executes below logic to swap the values of variable a and b.

Step 1: Multiply values of a and b and store it in variable a.
i.e.,
a = a * b;
50= 10 * 5;
So a = 50;

Step 2: Now divide value of b from value of a and store it in variable b.
i.e.,
b = a / b;
10= 50 / 5; (value of a = 50 according to Step 1)
So value of variable b is now 10.

Step 3: Now divide value of b from value of a and store it in variable a.
i.e.,
a = a / b;
5= 50 / 10; (Value of a = 50 from Step 1, and Value of b = 10 from Step 2)
Now the value of a = 5;

Finally value of a = 5(from step 3) and value of b = 10(from step 2).

This is how we swap the value of variable a and b by just making use of multiplication and division in C programming language.

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert