The Natural Logarithm can be approximated by the following series:
(x – 1 / x) + 1/2 (x – 1 / x)2 + 1/2 (x – 1 / x)3 + 1/2 (x – 1 / x)4 + ..
If x is input through the keyboard, write a C program to calculate the sum of first seven terms of this series.
Related Read:
For Loop In C Programming Language
Basic Arithmetic Operations In C
Video Tutorial: C Program To Calculate Sum of First 7 Terms of Natural Logarithm
[youtube https://www.youtube.com/watch?v=8mVIyfub9o4]
Source Code: C Program To Calculate Sum of First 7 Terms of Natural Logarithm
#include<stdio.h>
#include<math.h>
int main()
{
int count;
float x, result = 0.0;
printf("Enter value of x\n");
scanf("%f", &x);
for(count = 1; count <= 7; count++)
{
if(count == 1)
{
result = (x - 1) / x;
}
else
{
result = result + pow( (x - 1) / x, count) * 0.5;
}
}
printf("Result of first 7 terms = %0.2f\n", result);
return 0;
}
Output 1
Enter value of x
5
Result of first 7 terms = 1.98
Output 2
Enter value of x
14
Result of first 7 terms = 3.10
Logic To Calculate Sum of First 7 Terms of Natural Logarithm
According to the problem statement it is clear that we need sum of first 7 terms of Natural Logarithm. So we initialize the loop counter variable count to 1 and iterate through the for loop until count value is less than or equal to 7.
Inside for loop we calculate the value of first 7 terms in the series and store it inside variable result.
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