In boxing the weight class of a boxer is decided as per the following table. Write a C program that receives weight as input and prints out the boxer’s weight class.
Source Code: C Program To Determine Weight Class of a Boxer
#include < stdio.h >
int main()
{
int wt;
printf("Enter boxers weight in pounds\n");
scanf("%d", &wt);
if(wt < 115)
{
printf("Boxer is of weight class Flyweight\n");
}
else if(wt >= 115 && wt <= 121)
{
printf("Boxer is of weight class Bantamweight\n");
}
else if(wt >= 122 && wt <= 153)
{
printf("Boxer is of weight class Featherweight\n");
}
else if(wt >= 154 && wt <= 189)
{
printf("Boxer is of weight class Middleweight\n");
}
else if(wt >= 190)
{
printf("Boxer is of weight class Heavyweight\n");
}
return 0;
}
Output 1: Enter boxers weight in pounds 108 Boxer is of weight class Flyweight
Output 2: Enter boxers weight in pounds 120 Boxer is of weight class Bantamweight
Output 3: Enter boxers weight in pounds 140 Boxer is of weight class Featherweight
Output 4: Enter boxers weight in pounds 180 Boxer is of weight class Middleweight
Output 5: Enter boxers weight in pounds 200 Boxer is of weight class Heavyweight
A certain grade of steel is graded according to the following conditions:
1. Hardness must be greater than 50. 2. Carbon content must be less than 0.7 3. Tensile strength must be greater than 5600
The grades are as follows:
Grade is 10, if all three conditions are met. Grade is 9, if conditions 1 and 2 are met. Grade is 8, if conditions 2 and 3 are met. Grade is 7, if conditions 1 and 3 are met. Grade is 6, if only one condition is met. Grade is 5, if none of the conditions are met.
Write a C program, which will require the user to give values of hardness, carbon content and tensile strength of the steel under consideration and output the grade of the steel.
Note: Tensile strength is the maximum stress that a material can withstand while being stretched or pulled before breaking.
Output 1: Enter values of hardness, tensile Strength and Carbon Content in Steel 60 6000 0.5 Steel Grade is 10
Output 2: Enter values of hardness, tensile Strength and Carbon Content in Steel 80 5000 0.5 Steel Grade is 9
Output 3: Enter values of hardness, tensile Strength and Carbon Content in Steel 40 6000 0.5 Steel Grade is 8
Output 4: Enter values of hardness, tensile Strength and Carbon Content in Steel 60 8000 0.8 Steel Grade is 7
Output 5: Enter values of hardness, tensile Strength and Carbon Content in Steel 51 5000 0.8 Steel Grade is 6
Output 6: Enter values of hardness, tensile Strength and Carbon Content in Steel 41 5000 0.8 Steel Grade is 5
Update To The Program
If we input: Hardness: 50 Tensile Strength: 5600 Carbon Content: 0.7
Output will be: Steel Grade is 6.
If you check with Grade 6 condition inside if condition: ( hardness > 50 || carbon < 0.7 || ts > 5600 ) None of the condition is true. Condition for Grade 6 is: Grade is 6, if only one condition is met.
So our output is wrong. But why is it showing wrong result?
#include<stdio.h>
int main()
{
float x = 0.7;
printf("%d\n", sizeof(x));
printf("%d\n", sizeof(0.7));
printf("%d\n", sizeof(0.7f));
return 0;
}
Output: 4 8 4
As we can clearly see 0.7 is treated as double. We can typecase it using 0.7f. So in our steel program, variable declaration(float carbon) and comparison with 0.7(which is double) is causing the bug.
With this knowledge we can rewrite our program as follows:
Source Code: C Program To Find Grade of Steel
#include<stdio.h>
int main()
{
int hardness, ts;
double carbon;
printf("Enter values of hardness, tensile Strength and Carbon Content in Steel\n");
scanf("%d%d%lf", &hardness, &ts, &carbon);
if(hardness > 50 && carbon < 0.7 && ts > 5600)
{
printf("Steel Grade is 10\n");
}
else if(hardness > 50 && carbon < 0.7)
{
printf("Steel Grade is 9\n");
}
else if(carbon < 0.7 && ts > 5600)
{
printf("Steel Grade is 8\n");
}
else if(hardness > 50 && ts > 5600)
{
printf("Steel Grade is 7\n");
}
else if(hardness > 50 || carbon < 0.7 || ts > 5600)
{
printf("Steel Grade is 6\n");
}
else if(hardness < 50 && carbon > 0.7 && ts < 5600)
{
printf("Steel Grade is 5\n");
}
else
{
printf("Did not match any criteria\n");
}
return 0;
}
Output 1: Enter values of hardness, tensile Strength and Carbon Content in Steel 50 5600 0.7 Did not match any criteria
Output 2: Enter values of hardness, tensile Strength and Carbon Content in Steel 41 5000 0.8 Steel Grade is 5
In above program we’re declaring carbon as double and using %lf format specifier to take value of carbon as input from the user.
Typecasing 0.7 to floating point value
#include<stdio.h>
int main()
{
int hardness, ts;
float carbon;
printf("Enter values of hardness, tensile Strength and Carbon Content in Steel\n");
scanf("%d%d%f", &hardness, &ts, &carbon);
if(hardness > 50 && carbon < 0.7f && ts > 5600)
{
printf("Steel Grade is 10\n");
}
else if(hardness > 50 && carbon < 0.7f)
{
printf("Steel Grade is 9\n");
}
else if(carbon < 0.7f && ts > 5600)
{
printf("Steel Grade is 8\n");
}
else if(hardness > 50 && ts > 5600)
{
printf("Steel Grade is 7\n");
}
else if(hardness > 50 || carbon < 0.7f || ts > 5600)
{
printf("Steel Grade is 6\n");
}
else if(hardness < 50 && carbon > 0.7f && ts < 5600)
{
printf("Steel Grade is 5\n");
}
else
{
printf("Did not match any criteria\n");
}
return 0;
}
Output 1: Enter values of hardness, tensile Strength and Carbon Content in Steel 50 5600 0.7 Did not match any criteria
Output 2: Enter values of hardness, tensile Strength and Carbon Content in Steel 41 5000 0.8 Steel Grade is 5
Here we are typecasing 0.7 into floating point value by using 0.7f in else if conditions, which matches with the data type of variable carbon.
Any character is entered through the keyboard, write a C program to determine whether the character entered is a capital letter, a small case letter, a digit or a special symbol.
The following table shows the range of ASCII values for various characters: Character A – Z : ASCII Value 65 – 90 Character a – z : ASCII Value 97 – 122 Character 0 – 9 : ASCII Value 48 – 57 Special Symbol : ASCII Value 0 – 47, 58 – 64, 91 – 96, 123 – 127
Source Code: C Program To Check For Alphabet, Number and Special Symbol
#include<stdio.h>
int main()
{
char ch;
printf("Enter a Character\n");
scanf("%c", &ch);
if(ch >= 65 && ch <= 90)
{
printf("%c is an Uppercase Alphabet\n", ch);
}
else if(ch >= 97 && ch <= 122)
{
printf("%c is an lowercase Alphabet\n", ch);
}
else if(ch >= 48 && ch <= 57)
{
printf("%c is a Number\n", ch);
}
else if( (ch >= 0 && ch <= 47) ||
(ch >= 58 && ch <= 64) ||
(ch >= 91 && ch <= 96) ||
(ch >= 123 && ch <= 127))
{
printf("%c is a Special Character\n", ch);
}
return 0;
}
Output 1: Enter a Character A A is an Uppercase Alphabet
Output 2: Enter a Character i i is an lowercase Alphabet
Output 3: Enter a Character 8 8 is a Number
Output 4: Enter a Character $ $ is a Special Character
Logic To Check For Alphabet, Number and Special Symbol
We use &&(AND) operator check check for range. i.e., for number, we check from the range 48 to 57. To check if the user entered character lies in this range we use (ch >= 48 && ch <= 57). To check for multiple ranges we use ||(OR) operator. For example, for special symbol:
Logic To Check The Position of the Point in the graph We check for 9 conditions to determine the position of the user entered point in the graph. 1. Point lies on (0, 0): Origin 2. y = 0 and x > 0. i.e., x is positive: point lies on positive side of x-axis. 3. x = 0 and y > 0. i.e., y is positive: point lies on positive side of y-axis. 4. y = 0 and x < 0. i.e., x is negative: point lies on negative side of x-axis. 5. x = 0 and y < 0. i.e., y is negative: point lies on negative side of y-axis. 6. x > 0 and y > 0. i.e., both x and y are positive: point lies in First Quadrant. 7. x < 0 and y > 0. i.e., x is negative and y is positive: point lies in Second Quadrant. 8. x < 0 and y < 0. i.e., both x and y are negative: point lies in Third Quadrant. 9. x > 0 and y < 0. i.e., x is positive and y is negative: point lies in Forth Quadrant.
Expected Output for the Input
User Input: Enter the point(x, y) 5 5
Output: Point lies in First Quadrant
Video Tutorial: C Program To Check In Which Quadrant The Point Lies
Given a point (x, y), write a C program to find out if it lies on the x-axis, y-axis or on the origin(0, 0).
Important: Always remember that, to specify a point, we always write x-axis value first and then the y-axis value. i.e., (x, y)
Logic To Check If Point(x, y) Lies on x-axis or y-axis or Origin In point (x, y), if x = 0 and y = 0, then the point lies on the origin. If value of x is zero and y is greater than zero, then the point lies on y-axis. If y is zero and x is greater than zero, then the point lies on x-axis.
User Input: Enter the point(x, y) 0 5
Output: Point lies on y-axis
Video Tutorial: C Program To Check If Point Lies on x-axis or y-axis or Origin
