Tag: arithmetic operation

Simple Calculator Application In C

In this video tutorial we shall perform Addition, Subtraction, Multiplication and Division of numbers based on user input.

Related Read:
Basic Arithmetic Operations In C
Addition of 2 Numbers: C
Subtraction of 2 Numbers: C
Multiplication of 2 Numbers: C
Division of 2 Numbers: C
else if statement in C

Simple Calculator Program In C



YouTube Link: https://www.youtube.com/watch?v=QO6pCvM3xSQ [Watch the Video In Full Screen.]


Working of Calculator Program
We display list of operation one can perform. That is,

1. Addition
2. Subtraction
3. Multiplication
4. Division

We ask the user to input his / her choice for arithmetic operation. If the user selects 1, then we ask the user to enter 2 integer numbers to perform addition operation. Once the user enters 2 integer numbers we add and display the result on the screen.

If the user enters wrong choice, we ask the user to enter proper choice.

Student Grade Calculation using else-if clause

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  1.    
  2. #include < stdio.h >  
  3.   
  4. int main()  
  5. {  
  6.     int a, b, choice;  
  7.   
  8.     printf("Enter your choice\n");  
  9.     printf("1. Addition\n2. Subtraction\n3. Multiplication\n4. Division\n\n");  
  10.     scanf("%d", &choice);  
  11.   
  12.     if(choice > 4)  
  13.     {  
  14.         printf("You entered wrong choice\n");  
  15.     }  
  16.     else  
  17.     {  
  18.         printf("Enter 2 integer numbers\n");  
  19.         scanf("%d %d", &a, &b);  
  20.     }  
  21.   
  22.   
  23.     if(choice == 1)  
  24.     {  
  25.         printf("Addition of %d and %d is %d\n", a, b, (a+b));  
  26.     }  
  27.     else if(choice == 2)  
  28.     {  
  29.         printf("Subtraction of %d and %d is %d\n", a, b, (a-b));  
  30.     }  
  31.     else if(choice == 3)  
  32.     {  
  33.         printf("Multiplication of %d and %d is %d\n", a, b, (a*b));  
  34.     }  
  35.     else if(choice == 4)  
  36.     {  
  37.         if(b != 0)  
  38.             printf("Division of %d and %d is %d\n", a, b, (a/b));  
  39.         else  
  40.             printf("Number can not be divided by 0\n");  
  41.     }  
  42.     else  
  43.     {  
  44.         printf("Please enter any of these no 1, 2, 3, 4\n");  
  45.     }  
  46.   
  47.   
  48.     return 0;  
  49. }  

Output 1:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

1
Enter 2 integer numbers
3
2
Addition of 3 and 2 is 5

Output 2:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

2
Enter 2 integer numbers
8
3
Subtraction of 8 and 3 is 5

Output 3:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

3
Enter 2 integer numbers
5
5
Multiplication of 5 and 5 is 25

Output 4:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

4
Enter 2 integer numbers
10
2
Division of 10 and 2 is 5

Output 5:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

4
Enter 2 integer numbers
0
12
Division of 0 and 12 is 0

Output 6:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

4
Enter 2 integer numbers
10
0
Number can not be divided by 0

Output 7:
Enter your choice
1. Addition
2. Subtraction
3. Multiplication
4. Division

50
You entered wrong choice
Please enter any of these no 1, 2, 3, 4

Note: In division section(that is, choice 4) you can see nesting of if else statement. You can know more about nested if-else statements in this program: Nested if else Statement In C

Note: We can write the same program within while loop and ask the user if he wants to continue working inside calculator application. This avoids the need to exit and re-run the program. We’ll publish the code and video tutorial for the same in coming days. Stay subscribed to our YouTube Channel and blog.

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert