C - Part 53

C Program To Convert Cartesian To Polar Co-ordinates

Write a C program to receive Cartesian co-ordinates(x, y) of a point and convert them into Polar co-ordinates(r, θ).

Formula To Convert Cartesian To Polar Co-ordinates

r = sqrt(x*x + y*y);
OR
r = sqrt( pow(x, 2) + pow(y, 2) );

theta(θ) = atan(y/x);

where x and y are Cartesian co-ordinates.
atan() is the method in math.h library for calculating tan inverse.

Formula To Convert Radian To Degree

degree = radian * (180.0 / PI);
where PI is 3.141592

Source Code: Convert Cartesian To Polar Co-ordinates: C Program

 
#include < stdio.h >
#include < math.h >

int main()
{
    float x, y, r, theta;
    const float PI = 3.141592;

    printf("Enter Cartesian Co-ordinates(x, y)\n");
    scanf("%f%f", &x, &y);

    r     = sqrt(x*x + y*y);
    theta = atan(y/x);       // Radian

    theta = theta * (180.0 / PI); //Radian To Degree Conversion

    printf("Polar Co-ordinates: (r, theta) = (%f, %f)\n", r, theta);

    return 0;
}

Output:
Enter Cartesian Co-ordinates(x, y)
3
4
Polar Co-ordinates: (r, theta) = (5.000000, 53.130112)

Convert Cartesian To Polar Co-ordinates: C Program

[youtube https://www.youtube.com/watch?v=3ebGfJ_GOD0]

YouTube Link: https://www.youtube.com/watch?v=3ebGfJ_GOD0 [Watch the Video In Full Screen.]

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

Print All Trigonometric Ratios: C Program

If value of an angle is input through the keyboard, write a c program to print all its Trigonometric Ratios.

Formula To Convert Degree To Radian

radian = degree * (PI / 180.0);
where PI = 3.14159; (constant value)

Logic to Print all Trigonometric Ratios

First we ask the user to input angle of a Triangle in degrees. Next we convert angel from degrees to radian.

Next we include math.h header file and use methods present in it to get:
sin()
cos()
tan()

To get cosec() = 1 / sin();
To get sec() = 1 / cos();
To get cot() = 1 / tan();

tan() value can also be obtained using sin() / cos();
cot() value can also be obtained using cos() / sin();

Source Code: Print All Trigonometric Ratios: C Program

 
#include < stdio.h >
#include < math.h >

int main()
{
    float degree, radian;
    const float PI = 3.14159;

    printf("Enter angle in degree\n");
    scanf("%f", °ree);

    radian = degree * (PI / 180.0);

    printf("Sin(%f) = %f\n", degree, sin(radian));
    printf("Cos(%f) = %f\n", degree, cos(radian));
    printf("Tan(%f) = %f\n", degree, tan(radian));
    printf("Cosec(%f) = %f\n", degree, 1/sin(radian));
    printf("Sec(%f) = %f\n", degree, 1/cos(radian));
    printf("Cot(%f) = %f\n", degree, 1/tan(radian));

    return 0;
}

Output 1
Enter angle in degree
30
Sin(30.000000) = 0.500000
Cos(30.000000) = 0.866026
Tan(30.000000) = 0.577350
Cosec(30.000000) = 2.000001
Sec(30.000000) = 1.154700
Cot(30.000000) = 1.732052

Output 2
Enter angle in degree
45
Sin(45.000000) = 0.707106
Cos(45.000000) = 0.707107
Tan(45.000000) = 0.999999
Cosec(45.000000) = 1.414214
Sec(45.000000) = 1.414213
Cot(45.000000) = 1.000001

Print All Trigonometric Ratios: C Program

[youtube https://www.youtube.com/watch?v=-FMdZ456FUA]

YouTube Link: https://www.youtube.com/watch?v=-FMdZ456FUA [Watch the Video In Full Screen.]

Tan and Cot

 
    printf("Tan(%f) = %f\n", degree, sin(radian)/cos(radian));
    printf("Cot(%f) = %f\n", degree, cos(radian)/sin(radian));

 
    printf("Tan(%f) = %f\n", degree, tan(radian));
    printf("Cot(%f) = %f\n", degree, 1/tan(radian));

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C Program to Generate Odd Numbers Between Two Integers

C program to generate odd numbers between 2 integer values input by the user.

Note 1: An odd number is an integer that is not exactly divisible by 2.

Note 2: Odd numbers are of the form (2 * n + 1);

Note 3: Modular division( % ) returns remainder of division. For example, 10 / 2 = 5. But 10 % 2 = 0.

C Program to Generate Odd Numbers Between Two Integers

 
#include<stdio.h>

int main()
{
    int count, limit;

    printf("Enter start and end value to generate Odd numbers\n");
    scanf("%d%d", &count, &limit);

    printf("\nOdd numbers between %d and %d are:\n", count, limit);

    while(count <= limit)
    {
        if(count % 2 != 0)
        {
            printf("%d\n", count);
        }
        count++;
    }

    return 0;
}

Output 1
Enter start and end value to generate Odd numbers
10
30

Odd numbers between 10 and 30 are:
11
13
15
17
19
21
23
25
27
29

Output 2
Enter start and end value to generate Odd numbers
1
10

Odd numbers between 1 and 10 are:
1
3
5
7
9

C Program to Generate Odd Numbers Between Two Integers

[youtube https://www.youtube.com/watch?v=vPzV7pE0Djw]

YouTube Link: https://www.youtube.com/watch?v=vPzV7pE0Djw [Watch the Video In Full Screen.]

In above c program, we ask the user to input 2 integer value and store it in variables count and limit. While loop keeps executing until the start value i.e., count is less than or equal to the end value i.e., limit.

Inside while loop, for every value of count, we check if its not perfectly divisible by 2. If true, it’s a Odd number and we output that number to the console window. On every iteration of the loop we increment the value of count by 1.

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

C Program to Generate Even Numbers Between Two Integers

C program to generate even numbers between 2 integer values input by the user.

Note 1: An even number is an integer that is exactly divisible by 2.

Note 2: Even numbers are of the form 2 * n;

Note 3: Modular division( % ) returns remainder of division. For example, 10 / 2 = 5. But 10 % 2 = 0.

C Program to Generate Even Numbers Between Two Integers

 
#include<stdio.h>

int main()
{
    int count, limit;

    printf("Enter start value and end value to generate Even no's\n");
    scanf("%d%d", &count, &limit);

    printf("\nEven numbers between %d and %d are:\n", count, limit);

    while(count <= limit)
    {
        if(count % 2 == 0)
        {
            printf("%d\n", count);
        }
        count++;
    }

    return 0;
}

Output 1
Enter start value and end value to generate Even no’s
10
30

Even numbers between 10 and 30 are:
10
12
14
16
18
20
22
24
26
28
30

Output 2
Enter start value and end value to generate Even no’s
1
10

Even numbers between 1 and 10 are:
2
4
6
8
10

C Program to Generate Even Numbers Between Two Integers

[youtube https://www.youtube.com/watch?v=cE25_Fm7eMU]

YouTube Link: https://www.youtube.com/watch?v=cE25_Fm7eMU [Watch the Video In Full Screen.]

Inside while loop, for every value of count, we check if its perfectly divisible by 2. If true, it’s a Even number and we output that number to the console window. On every iteration of the loop we increment the value of count by 1.

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

Update:
In the above video I’ve said: “count should be exactly divisible by 0”.

I’m sorry about that. It should be – “Value inside variable count should be exactly divisible by 2.”

Find Area of a Triangle Using Its Base and Height: C Program

Find the area of the Triangle when it’s base and height are input by the user.

Formula To Calculate Area of Triangle when its Base and Height are given

Area = (Base * Height) / 2.0;

Note: If we divide an expression or number by 2, it’ll return only the integer part and the decimal part will be discarded. So we are dividing the expression by 2.0 (which is of type double).

Find Area of a Triangle Using Its Base and Height: C Program

[youtube https://www.youtube.com/watch?v=Vk3sB2G2pI8]

YouTube Link: https://www.youtube.com/watch?v=Vk3sB2G2pI8 [Watch the Video In Full Screen.]

Find Area of a Triangle Using Its Base and Height: C Program

#include < stdio.h >

int main()
{
    float base, height, area;

    printf("Enter length of base of Triangle\n");
    scanf("%f", &base);

    printf("Enter length of height of Triangle\n");
    scanf("%f", &height);

    area = (base * height) / 2.0;

    printf("Area of Triangle is %0.2f\n", area);

    return 0;
}

Output:
Enter length of base of Triangle
15
Enter length of height of Triangle
25
Area of Triangle is 187.50

Validate the Input and Find Area of Triangle: C Program

#include < stdio.h >

int main()
{
    float base, height, area;

    printf("Enter length of base of Triangle\n");
    scanf("%f", &base);

    printf("Enter length of height of Triangle\n");
    scanf("%f", &height);

    if(base == 0 || height == 0)
    {
        printf("Invalid Input\n");
    }
    else
    {
        area = (base * height) / 2.0;
        printf("Area of Triangle is %0.2f\n", area);
    }

    return 0;
}

Output 1:
Enter length of base of Triangle
0
Enter length of height of Triangle
25
Invalid Input

Output 2:
Enter length of base of Triangle
15
Enter length of height of Triangle
30
Area of Triangle is 225.00

Note: Note that the area of Triangle has only 2 digits after the decimal point. That is because we have %0.2f as format specifier in the printf method where we are printing out the area of Triangle.

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert