nested if else

Biggest of 3 Numbers: C

Lets write C program to find biggest of 3 numbers, using nested if else statement.

Biggest of 3 Numbers Using Ternary Operator: C

C Program To Find Biggest of 3 numbers

 
#include < stdio.h >

int main()
{
    int a, b, c;

    printf("Enter 3 numbers\n");
    scanf("%d %d %d", &a, &b, &c);

    if( a > b && a > c)
    {
        printf("%d is biggest\n", a);
    }
    else
    {
        if( b > c )
        {
            printf("%d is biggest\n", b);
        }
        else
        {
            printf("%d is biggest\n", c);
        }
    }

    return 0;
}

Output 1:
Enter 3 numbers
1
2
3
3 is biggest

Output 2:
Enter 3 numbers
10
18
15
18 is biggest

Here first we check if a is greater than b. If yes, then we display a as big. Else b or c is biggest. So now we check if b is greater than c, if yes, we display b as biggest else c is biggest. Nested if else condition works great for programs like this.

Biggest of 3 numbers: C Program

YouTube Link: https://www.youtube.com/watch?v=iy–Q0cLnfc [Watch the Video In Full Screen.]

C Program To Find Biggest of 3 numbers

 
#include < stdio.h >

int main()
{
    int a, b, c, big;

    printf("Enter 3 numbers\n");
    scanf("%d %d %d", &a, &b, &c);

    if( a > b && a > c)
    {
        big = a;
    }
    else
    {
        if( b > c )
        {
            big = b;
        }
        else
        {
            big = c;
        }
    }

    printf("Biggest of 3 number is %d\n", big);

    return 0;
}

Output:
Enter 3 numbers
500
550
555
Biggest of 3 number is 555

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C Program To Check Leap Year

C Program to Find if a given Year is a Leap Year or Not.

Leap Year Logic

Leap Year
1. If a year is a century year(years ending with 00) and if it’s perfectly divisible by 400, then it’s a leap year.
2. If the given year is not a century year and it’s perfectly divisible by 4, then it’s a leap year.

Not Leap Year
1. If the year entered is a century year(perfectly divisible by 100), but not perfectly divisible by 400. Then it’s not a leap year.
2. A year which is not a century year and is not perfectly divisible by 4 is not a leap year.

Leap Year Program: C Programming

YouTube Link: https://www.youtube.com/watch?v=rO4LIxeaD6A [Watch the Video In Full Screen.]

In this video tutorial: inside if block we first check if the entered number is a century year. If yes, then we see if it’s perfectly divisible by 400. If true, then its a leap year. If not, its not a leap year.

If the control shifts to else block then the entered year is not a century year. So we check if the year is perfectly divisible by 4. If yes, then it’s a leap year. If not, it’s not a leap year.

Source Code For Leap Year Program: C Programming

 
#include < stdio.h >

int main()
{
    int year;

    printf("Enter the year\n");
    scanf("%d", &year);

    if(year % 100 == 0)
    {
        if(year % 400 == 0)
        {
            printf("%d is leap year!\n", year);
        }
        else
        {
            printf("%d is not leap year!\n", year);
        }
    }
    else
    {
        if(year % 4 == 0)
        {
            printf("%d is leap year!\n", year);
        }
        else
        {
            printf("%d is not leap year!\n", year);
        }
    }

    return 0;
}

Output 1:
Enter the year
2019
2019 is not leap year!

Output 2:
Enter the year
2020
2020 is leap year!

Output 3:
Enter the year
2000
2000 is leap year!

List of some leap years

2000
2004
2008
2012
2016
2020
2024
2028
2032
2036
2040
2044
2048

You can run the program and input any of the above leap year and check for the output.

This program is also a perfect example for nested if else.

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

Nested if else Statement In C

In this program we’ll show you nesting of if else statements. Here we are illustrating the concept by taking score/marks of 5 subject from the user. Then we calculate the percentage of it and display grade to the user.

Simple Logic

When the condition in if statement is false then only else block gets executed. In our program, we check, if percentage is greater than or equal to 60. If it is false, then only control shifts to else block. So inside else(nested if else) we need not once again check if the percentage is less than 60.

Note: We are not using else if and logical operator in this C program purposefully. We want to show nesting of if else in this program.

 
#include < stdio.h >

int main()
{
    float s1, s2, s3, s4, s5, per;

    printf("Enter marks of 5 subject\n");
    scanf("%f %f %f %f %f", &s1, &s2, &s3, &s4, &s5);

    per = (s1 + s2 + s3 + s4 + s5) / 5.0;

    if(per >= 60)
    {
        printf("Grade A\n");
    }
    else
    {
        if(per >= 50)
        {
            printf("Grade B\n");
        }
        else
        {
            if(per >= 40)
            {
                printf("Grade C\n");
            }
            else
            {
                printf("Failed!\n");
            }
        }
    }

    return 0;
}

Output 1:
Enter marks of 5 subject
59
60
62
61
63
Grade A

Output 2:
Enter marks of 5 subject
59
55
56
53
58
Grade B

Output 3:
Enter marks of 5 subject
49
45
46
49
48
Grade C

Output 4:
Enter marks of 5 subject
39
45
25
36
35
Failed!

Student Grade Calculation using Nested if else: C Program

YouTube Link: https://www.youtube.com/watch?v=I-EHRu-Nq8o [Watch the Video In Full Screen.]

Note: In next video we’ll show you how to perform the same operation as shown in above C program, using else-if and logical operators.

Also check the program C Program To Check Leap Year for a perfect nested if else example.

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert