Video Tutorial to illustrate, C Program to find sum of digits in the given/user entered integer number.
In this program we assign variable sum = 0 to avoid garbage values in sum before the calculation, which would result in wrong output.
We store the user entered value in num.
1 2 3 4 5 6 | while( num ) { rem = num % 10; sum = sum + rem; num = num / 10; } |
Here the loop executes until the value of num is zero.
If user enters 123, we apply the modulus to get the individual values.
Ex:
123 % 10 = 3
12 % 10 = 2
1 % 10 = 1
We get 123, 12 and 1 by dividing the original value by 10.
Ex:
123 user entered value.
123 / 10 = 12
12 / 10 = 1
Now the sum.
sum = sum + rem;
3 = 0 + 3
5 = 3 + 2
6 = 5 + 1
So the sum of digits in the given integer number is 6.
Video Tutorial: Find Sum of Digits In A Given Number: C
[youtube https://www.youtube.com/watch?v=UnXfCTtHNWw]
Full Free Source code
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 | #include < stdio.h > #include < conio.h > void main() { int num, rem, sum = 0; clrscr(); printf("Enter an integer number\n"); scanf("%d", &num); while(num) { rem = num % 10; sum = sum + rem; num = num / 10; } printf("\nThe sum of digits is %d", sum); getch(); } |
Output:
Enter an integer number
123
The sum of digits is 6