for loop - Part 5

C Program To Calculate Amount In Compound Interest

When interest compounds q times per year at an annual rate of r % for n years, the principal p compounds to an amount a as per the following formula:

a = p (1 + r / q) ^nq

Write a C Program to read 10 sets of p, r, n & q and calculate the corresponding a‘s.

Video Tutorial: C Program To Calculate Amount In Compound Interest

[youtube https://www.youtube.com/watch?v=7q8yFP6S3MA]

YouTube Link: https://www.youtube.com/watch?v=7q8yFP6S3MA [Watch the Video In Full Screen.]

Logic To Find Compounded Amount

We ask the user to enter values for floating point variables p, n, r and q. We use the formula:

a = p (1 + r / q) ^nq

And display the result to the console window.

where,
p – principal amount;
n – number of years.
r – rate of interest;
q – number of times interest compounds per year.

Note: We need to convert the user entered interest into percentage by dividing the integer number by 100.

Source Code: C Program To Calculate Amount In Compound Interest

 
#include<stdio.h>
#include<math.h>

int main()
{
    float p, n, r, q, a;
    int count;

    for(count = 1; count <= 10; count++)
    {
        printf("Enter principal amount\n");
        scanf("%f", &p);

        printf("Enter number of years\n");
        scanf("%f", &n);

        printf("Enter rate of interest\n");
        scanf("%f", &r);

        r = r / 100;

        printf("Enter no of times you compound per year\n");
        scanf("%f", &q);

        a = p * pow( (1 + (r/q)), n * q );

        printf("Compounded amount is %f\n\n", a);
    }

    return 0;
}

Output
Enter principal amount
5000
Enter number of years
2
Enter rate of interest
8
Enter no of times you compound per year
4
Compounded amount is 5858.296875

Enter principal amount
1000
Enter number of years
7
Enter rate of interest
5
Enter no of times you compound per year
1
Compounded amount is 1407.100464

Enter principal amount
2000
Enter number of years
5
Enter rate of interest
12
Enter no of times you compound per year
12
Compounded amount is 3633.393311

Enter principal amount
5000
Enter number of years
5
Enter rate of interest
5
Enter no of times you compound per year
5
Compounded amount is 6412.160156

Enter principal amount

Note: Above program keeps on iterating 10 times and asks the input 10 times.

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C Program To Find Odd Numbers Between Range using For Loop

Lets write a C program to generate odd numbers between 2 integer values input by the user using For loop.

Note 1: An odd number is an integer that is not exactly divisible by 2.

Note 2: Odd numbers are of the form (2 * number + 1);

Note 3: Modular division( % ) returns remainder of division. For example, 10 / 2 = 5. But 10 % 2 = 0.

Video Tutorial: C Program To Find Odd Numbers Between Range using For Loop

[youtube https://www.youtube.com/watch?v=P85sziIyIdA]

YouTube Link: https://www.youtube.com/watch?v=P85sziIyIdA [Watch the Video In Full Screen.]

In above c program, we ask the user to input 2 integer value and store it in variables start and end. If value of start is greater than the value of end, then we swap the values.

For loop counter is initialized to start, and for loop executes until value of count is less than or equal to end. For each iteration of the for loop, count value increments by 1.

Inside for loop, for every value of count, we check if its not perfectly divisible by 2. If true, it’s a Odd number and we output that number to the console window.

Source Code: C Program To Find Odd Numbers Between Range using For Loop

 
#include<stdio.h>

int main()
{
    int start, end, temp, count;

    printf("Enter start and end value, to find odd numbers\n");
    scanf("%d%d", &start, &end);

    if(start > end)
    {
        temp  = start;
        start = end;
        end   = temp;
    }

    printf("Odd numbers between %d and %d are\n", start, end);

    for(count = start; count <= end; count++)
    {
        if(count % 2 != 0)
            printf("%d\n", count);
    }

    return 0;
}

Output 1
Enter start and end value, to find odd numbers
40
60
Odd numbers between 40 and 60 are
41
43
45
47
49
51
53
55
57
59

Output 2
Enter start and end value, to find odd numbers
60
40
Odd numbers between 40 and 60 are
41
43
45
47
49
51
53
55
57
59

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For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

C Program To Find Even Numbers Between Range using For Loop

Lets write a C program to find all the even numbers between 2 integer values input by the user, using for loop.

Note 1: An even number is an integer that is exactly divisible by 2. That is reminder of division should be zero.

Note 2: Even numbers are of the form 2 * number;

Note 3: Modular division( % ) returns remainder of division. For example, 10 / 2 = 5. But 10 % 2 = 0.

Video Tutorial: C Program to Find Even Numbers Between Range using For Loop

[youtube https://www.youtube.com/watch?v=WCCbJY_9gQQ]

YouTube Link: https://www.youtube.com/watch?v=WCCbJY_9gQQ [Watch the Video In Full Screen.]

In above c program, we ask the user to input 2 integer value and store it in variables start and end. For loop counter is initialized to start and for loop executes until loop counter is less than or equal to value of end. For each iteration of the for loop, loop counter value increments by 1.

Inside for loop, for every value of count, we check if its perfectly divisible by 2. If true, it’s a Even number and we output that number to the console window.

Source Code: C Program to Find Even Numbers Between Range using For Loop

 
#include<stdio.h>

int main()
{
    int start, end, count, temp;

    printf("Enter start value and end value to generate Even no's\n");
    scanf("%d%d", &start, &end);

    if(start > end)
    {
        temp  = start;
        start = end;
        end   = temp;
    }

    printf("Even numbers between %d and %d are:\n", start, end);

    for(count = start; count <= end; count++)
    {
        if(count % 2 == 0)
        {
            printf("%d\n", count);
        }
    }

    return 0;
}

Output 1
Enter start value and end value to generate Even no’s
10
20
Even numbers between 10 and 20 are:
10
12
14
16
18
20

Output 2
Enter start value and end value to generate Even no’s
50
40
Even numbers between 40 and 50 are:
40
42
44
46
48
50

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For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

C Program To Generate Fibonacci Series using For Loop

Lets write a C program to generate Fibonacci Series, using for loop.

First Thing First: What Is Fibonacci Series ?
Fibonacci Series is a series of numbers where the first two Fibonacci numbers are 0 and 1, and each subsequent number is the sum of the previous two. Its recurrence relation is given by F_n = F_n-1 + F_n-2.

Below are a series of Fibonacci numbers(10 numbers):
0
1
1
2
3
5
8
13
21
34

How Its Formed:
0 <– First Number (n1)
1 <– Second Number (n2)
1 <– = 1 + 0
2 <– = 1 + 1
3 <– = 2 + 1
5 <– = 3 + 2
8 <– = 5 + 3
13 <– = 8 + 5
21 <– = 13 + 8
34 <– = 21 + 13

Video Tutorial: C Program To Generate Fibonacci Series using For Loop

[youtube https://www.youtube.com/watch?v=8VJVcwuYDPw]

YouTube Link: https://www.youtube.com/watch?v=8VJVcwuYDPw [Watch the Video In Full Screen.]

Source Code: C Program To Generate Fibonacci Series using For Loop

#include<stdio.h>

int main()
{
    int n1 = 0, n2 = 1, n3, count, num;

    printf("Enter the number of terms to be printed\n");
    scanf("%d", &num);

    printf("\n%d\n%d\n", n1, n2);

    for(count = 3; count <= num; count++)
    {
        n3 = n1 + n2;
        printf("%d\n", n3);

        n1 = n2;
        n2 = n3;
    }

    return 0;
}

Output:
Enter the number of terms to be printed
10

0
1
1
2
3
5
8
13
21
34

Logic To Generate Fibonacci Series using For Loop

We know that the first 2 digits in Fibonacci series are 0 and 1. So we directly initialize n1 and n2 to 0 and 1 respectively and print that out before getting into For loop logic. Since we’ve already printed two Fibonacci numbers, we assign 3 to loop control variable count and iterate through the for loop till count is less than or equal to the user entered number.

Inside For loop
As per definition of Fibonacci series: “..each subsequent number is the sum of the previous two.” So we add n1 and n2 and assign the result to n3 and display the value of n3 to the console.

Next, we step forward to get next Fibonacci number in the series, so we step forward by assigning n2 value to n1 and n3 value to n2.

For loop keeps repeating above steps until the count is less than or equal to the user entered number. If the user entered limit/count is 10, then the loop executes 8 times(as we already printed the first two numbers in the Fibonacci series, that is, 0 and 1).

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For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

C Program To Print Multiplication Table Using For Loop

Lets write a C program to print the multiplication table of the number entered by the user. The table should get displayed in the following form:

Example: Multiplication table of 29
29 x 1 = 29
29 x 2 = 58
29 x 3 = 87
29 x 4 = 116
29 x 5 = 145
29 x 6 = 174
29 x 7 = 203
29 x 8 = 232
29 x 9 = 261
29 x 10 = 290

Simple Mathematical Trick — logical thinking

C Program To Print Multiplication Table Using For Loop

[youtube https://www.youtube.com/watch?v=fjEYZStx5_I]

YouTube Link: https://www.youtube.com/watch?v=fjEYZStx5_I [Watch the Video In Full Screen.]

Source Code: C Program To Print Multiplication Table Using For Loop

 
#include<stdio.h>

int main()
{
    int num, count;

    printf("Enter a number\n");
    scanf("%d", &num);

    printf("Multiplication table for %d is:\n", num);

    for(count = 1; count <= 10; count++)
    {
        printf("%d x %d = %d\n", num, count, (num*count));
    }

    return 0;
}

Output 1:
Enter a number
5
Multiplication table for 5 is:
5 x 1 = 5
5 x 2 = 10
5 x 3 = 15
5 x 4 = 20
5 x 5 = 25
5 x 6 = 30
5 x 7 = 35
5 x 8 = 40
5 x 9 = 45
5 x 10 = 50

Output 2:
Enter a number
10
Multiplication table for 10 is:
10 x 1 = 10
10 x 2 = 20
10 x 3 = 30
10 x 4 = 40
10 x 5 = 50
10 x 6 = 60
10 x 7 = 70
10 x 8 = 80
10 x 9 = 90
10 x 10 = 100

Output 3:
Enter a number
7
Multiplication table for 7 is:
7 x 1 = 7
7 x 2 = 14
7 x 3 = 21
7 x 4 = 28
7 x 5 = 35
7 x 6 = 42
7 x 7 = 49
7 x 8 = 56
7 x 9 = 63
7 x 10 = 70

Output 4:
Enter a number
6
Multiplication table for 6 is:
6 x 1 = 6
6 x 2 = 12
6 x 3 = 18
6 x 4 = 24
6 x 5 = 30
6 x 6 = 36
6 x 7 = 42
6 x 8 = 48
6 x 9 = 54
6 x 10 = 60

Logic: Multiplication Table

We ask the user to enter a number. We initialize for loop counter to 1 and iterate through the loop until loop counter is less than or equal to 10. Inside for loop we multiply the user entered number with the loop counter variable to get the result of multiplication table.

You can also watch C Program To Print Multiplication Table Using While Loop video tutorial.

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert