Logic To Find Sum of Squares of Numbers from 1 to N, using While Loop
We ask the user to enter the limit. We initialize variable count to 1. Now inside while loop we square the value of variable count and add it to the previous value of variable sum – we repeat this for each iteration of while loop until value of count is less than or equal to value entered by the user(which is stored in variable N). For each iteration of the while loop value of variable count is incremented by 1.
Video Tutorial: C Program To Find Sum of Squares of Numbers from 1 to N, using While Loop
printf("Sum of squares of numbers from 1 to %d is %d.\n", N, sum);
return 0;
}
#include < stdio.h >
int main()
{
int N, count = 1, sum = 0;
printf("Enter the limit\n");
scanf("%d", &N);
while(count <= N)
{
sum = sum + (count * count);
count++;
}
printf("Sum of squares of numbers from 1 to %d is %d.\n", N, sum);
return 0;
}
Output: Enter the limit 5 Sum of squares of numbers from 1 to 5 is 55.
Lets write a C program to see how to use sizeof() method or function in C programming language.
sizeof() is a builtin method/function present in C programming. It is used to calculate the size(in bytes) that a datatype occupies in the computers memory.
sizeof() method takes a single argument and it is not a function whose value is determined at run time, but rather an operator whose value is determined by compiler – so it’s called as compile time unary operator.
sizeof() method can be used with primitive data type like int, float, char or user defined data types like structures, unions etc.
Video Tutorial: Sizeof Operator in C Programming Language
printf("Size of a single character is %d byes\n", sizeof(s));
printf("Size of a character array s1[10] is %d byes\n", sizeof(s1));
printf("Size of a integer is %d byes\n", sizeof(a));
printf("Size of a long integer is %d byes\n", sizeof(longint));
printf("Size of a long long integer is %d byes\n", sizeof(longlongint));
printf("Size of a integer array a1[10] is %d byes\n", sizeof(a1));
printf("Size of a float is %d byes\n", sizeof(float));
printf("Size of a double is %d byes\n", sizeof(double));
printf("Size of a long double is %d byes\n", sizeof(longdouble));
printf("Size of a b+c is %d byes\n", sizeof(b+c));
return 0;
}
#include < stdio.h >
int main()
{
int a, a1[10];
char s;
char s1[10];
int b = 10, c = 5;
printf("Size of a single character is %d byes\n", sizeof(s));
printf("Size of a character array s1[10] is %d byes\n", sizeof(s1));
printf("Size of a integer is %d byes\n", sizeof(a));
printf("Size of a long integer is %d byes\n", sizeof(long int));
printf("Size of a long long integer is %d byes\n", sizeof(long long int));
printf("Size of a integer array a1[10] is %d byes\n", sizeof(a1));
printf("Size of a float is %d byes\n", sizeof(float));
printf("Size of a double is %d byes\n", sizeof(double));
printf("Size of a long double is %d byes\n", sizeof(long double));
printf("Size of a b+c is %d byes\n", sizeof(b+c));
return 0;
}
Output: Size of a single character is 1 byes Size of a character array s1[10] is 10 byes Size of a integer is 4 byes Size of a long integer is 4 byes Size of a long long integer is 8 byes Size of a integer array a1[10] is 40 byes Size of a float is 4 byes Size of a double is 8 byes Size of a long double is 12 byes Size of a b+c is 4 byes
printf("Size of short data type is %d\n", sizeof(short));
printf("Size of integer data type is %d\n", sizeof(int));
printf("Size of long integer data type is %d\n", sizeof(longint));
printf("Size of long long integer data type is %d\n", sizeof(longlongint));
return 0;
}
#include < stdio.h >
int main()
{
printf("Size of short data type is %d\n", sizeof(short));
printf("Size of integer data type is %d\n", sizeof(int));
printf("Size of long integer data type is %d\n", sizeof(long int));
printf("Size of long long integer data type is %d\n", sizeof(long long int));
return 0;
}
Output: Size of short data type is 2 Size of integer data type is 4 Size of long integer data type is 4 Size of long long integer data type is 8
Lets write a C program to convert a number from Octal number system(base 8) to Binary number system(base 2), using while loop.
In this C program we first convert the user entered number from Octal number system to Decimal number system. Then we take the result(which is in Decimal number system) and convert to Binary number system.
Number Systems
1. Binary Number System uses base 2 and digits 01. 2. Octal Number System uses base 8 and digits 01234567. 3. Decimal Number System uses base 10 and digits 0123456789. 4. Hexadecimal Number System uses base 16 and digits 0123456789ABCDEF.
printf("Binary Equivalent of Octal no %d is ", num);
while(num)
{
rem = num % 10;
dec = dec + rem * pow(8, place);
num = num / 10;
place++;
}
place = 1;
rem = 0;
while(dec)
{
rem = dec % 2;
bin = bin + (rem * place);
dec = dec / 2;
place = place * 10;
}
printf("%ld.\n", bin);
return 0;
}
#include < stdio.h >
#include < math.h >
int main()
{
int num, dec = 0, rem = 0, place = 0;
long bin = 0;
printf("Enter an Octal Number\n");
scanf("%d", &num);
printf("Binary Equivalent of Octal no %d is ", num);
while(num)
{
rem = num % 10;
dec = dec + rem * pow(8, place);
num = num / 10;
place++;
}
place = 1;
rem = 0;
while(dec)
{
rem = dec % 2;
bin = bin + (rem * place);
dec = dec / 2;
place = place * 10;
}
printf("%ld.\n", bin);
return 0;
}
Output 1: Enter an Octal Number 71 Binary Equivalent of Octal no 71 is 111001.
Output 2: Enter an Octal Number 11 Binary Equivalent of Octal no 11 is 1001.
Lets write a C program to convert a number from Binary number system(base 2) to Octal number system(base 8), using while loop.
In this C program we first convert the user entered number from Binary number system to Decimal number system. Then we take the result(which is in Decimal number system) and convert to Octal number system.
Number Systems
1. Binary Number System uses base 2 and digits 01. 2. Octal Number System uses base 8 and digits 01234567. 3. Decimal Number System uses base 10 and digits 0123456789. 4. Hexadecimal Number System uses base 16 and digits 0123456789ABCDEF.
printf("\nOctal Equivalent of Binary no %ld is ", num);
while(num)
{
rem = num % 10;
dec = dec + rem * pow(2, place);
num = num / 10;
place++;
}
place = 1;
rem = 0;
while(dec)
{
rem = dec % 8;
oct = oct + rem * place;
dec = dec / 8;
place = place * 10;
}
printf("%d.\n", oct);
return 0;
}
#include < stdio.h >
#include < math.h >
int main()
{
long num;
int dec = 0, oct = 0, rem = 0, place = 0;
printf("Enter a Binary Number\n");
scanf("%ld", &num);
printf("\nOctal Equivalent of Binary no %ld is ", num);
while(num)
{
rem = num % 10;
dec = dec + rem * pow(2, place);
num = num / 10;
place++;
}
place = 1;
rem = 0;
while(dec)
{
rem = dec % 8;
oct = oct + rem * place;
dec = dec / 8;
place = place * 10;
}
printf("%d.\n", oct);
return 0;
}
