Perform Binary Addition : I/P to the function

[RoboCop]

Implement a function that performs binary addition; Input to the function is 2 constant strings. The function returns a string that holds result of addition.

Ex: “1001” + “101” = “1110”

char* binaryadd(const char *a, const char *b) { }

[Satish]

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>

long bintodeci(long n)
{
  int base = 1, rem;
  long res = 0;

  while( n > 0 )
  {
    rem = n % 10;
    res = res + rem * base;
    base= base * 2;
    n   = n / 10;
  }
  return(res);
}

long decitobin(long n)
{
  int base = 1, rem;
  long res = 0;

  while( n > 0 )
  {
    rem = n % 2;
    res = res + rem * base;
    base= base * 10;
    n   = n / 2;  
  }
  return(res);
}


char* binaryadd(const char *a, const char *b)
{
  long no1, no2, res;
  char *ep;

  no1 = atol(a);
  no2 = atol(b);

  no1 = bintodeci(no1);
  no2 = bintodeci(no2);

  res = no1 + no2;

  res = decitobin(res);

  ltoa(res, ep, 10);
 
  // printf("%ld", res);

  return(ep);
}


void main()
{
  char *result;
  clrscr();

  result = binaryadd("100", "111");
  
  printf("Result = %s", result);

  getch();
}

[Author]

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