C - Part 28

C Program To Find Odd Numbers Between Range using For Loop

Lets write a C program to generate odd numbers between 2 integer values input by the user using For loop.

Note 1: An odd number is an integer that is not exactly divisible by 2.

Note 2: Odd numbers are of the form (2 * number + 1);

Note 3: Modular division( % ) returns remainder of division. For example, 10 / 2 = 5. But 10 % 2 = 0.

Video Tutorial: C Program To Find Odd Numbers Between Range using For Loop

[youtube https://www.youtube.com/watch?v=P85sziIyIdA]

YouTube Link: https://www.youtube.com/watch?v=P85sziIyIdA [Watch the Video In Full Screen.]

In above c program, we ask the user to input 2 integer value and store it in variables start and end. If value of start is greater than the value of end, then we swap the values.

For loop counter is initialized to start, and for loop executes until value of count is less than or equal to end. For each iteration of the for loop, count value increments by 1.

Inside for loop, for every value of count, we check if its not perfectly divisible by 2. If true, it’s a Odd number and we output that number to the console window.

Source Code: C Program To Find Odd Numbers Between Range using For Loop

 
#include<stdio.h>

int main()
{
    int start, end, temp, count;

    printf("Enter start and end value, to find odd numbers\n");
    scanf("%d%d", &start, &end);

    if(start > end)
    {
        temp  = start;
        start = end;
        end   = temp;
    }

    printf("Odd numbers between %d and %d are\n", start, end);

    for(count = start; count <= end; count++)
    {
        if(count % 2 != 0)
            printf("%d\n", count);
    }

    return 0;
}

Output 1
Enter start and end value, to find odd numbers
40
60
Odd numbers between 40 and 60 are
41
43
45
47
49
51
53
55
57
59

Output 2
Enter start and end value, to find odd numbers
60
40
Odd numbers between 40 and 60 are
41
43
45
47
49
51
53
55
57
59

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

C Program To Find Even Numbers Between Range using For Loop

Lets write a C program to find all the even numbers between 2 integer values input by the user, using for loop.

Note 1: An even number is an integer that is exactly divisible by 2. That is reminder of division should be zero.

Note 2: Even numbers are of the form 2 * number;

Note 3: Modular division( % ) returns remainder of division. For example, 10 / 2 = 5. But 10 % 2 = 0.

Video Tutorial: C Program to Find Even Numbers Between Range using For Loop

[youtube https://www.youtube.com/watch?v=WCCbJY_9gQQ]

YouTube Link: https://www.youtube.com/watch?v=WCCbJY_9gQQ [Watch the Video In Full Screen.]

In above c program, we ask the user to input 2 integer value and store it in variables start and end. For loop counter is initialized to start and for loop executes until loop counter is less than or equal to value of end. For each iteration of the for loop, loop counter value increments by 1.

Inside for loop, for every value of count, we check if its perfectly divisible by 2. If true, it’s a Even number and we output that number to the console window.

Source Code: C Program to Find Even Numbers Between Range using For Loop

 
#include<stdio.h>

int main()
{
    int start, end, count, temp;

    printf("Enter start value and end value to generate Even no's\n");
    scanf("%d%d", &start, &end);

    if(start > end)
    {
        temp  = start;
        start = end;
        end   = temp;
    }

    printf("Even numbers between %d and %d are:\n", start, end);

    for(count = start; count <= end; count++)
    {
        if(count % 2 == 0)
        {
            printf("%d\n", count);
        }
    }

    return 0;
}

Output 1
Enter start value and end value to generate Even no’s
10
20
Even numbers between 10 and 20 are:
10
12
14
16
18
20

Output 2
Enter start value and end value to generate Even no’s
50
40
Even numbers between 40 and 50 are:
40
42
44
46
48
50

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

C Program To Calculate Approximate Level of Intelligence of a Person

According to a study, the approximate level of intelligence of a person can be calculated using the following formula:

i = 2 + ( y + 0.5x )

Write a C program that will produce a table of values of i, y and x, where y varies from 1 to 6, and, for each value of y, x varies from 5.5 to 12.5 in steps 0.5.

Logic To understanding the problem statement

1. Problem statement snippet: “..y varies from 1 to 6”. That means, we can accomplish it using a looping statement. So we can take a for loop and initialize variable y to 1 and iterate the for loop until y is less than or equal to 6.

2. Problem statement snippet: “..for each value of y, x varies from”. That means we should write a nested for loop here.

3. Problem statement snippet: “..for each value of y, x varies from 5.5 to 12.5 in steps 0.5”. That means, we need to write a nested for loop and initialize x value to 5.5 and iterate through the for loop until x value is less than or equal to 12.5 And for each iteration of the inner for loop we need to increment the value of x by 0.5

Video Tutorial: C Program To Calculate Approximate Level of Intelligence of a Person

[youtube https://www.youtube.com/watch?v=wRfgDzMMIvY]

YouTube Link: https://www.youtube.com/watch?v=wRfgDzMMIvY [Watch the Video In Full Screen.]

Source Code: C Program To Calculate Approximate Level of Intelligence of a Person

#include<stdio.h>

int main()
{
    int y, count = 1;
    float i, x;

    for(y = 1; y <= 6; y++)
    {
        for(x = 5.5; x <= 12.5; x += 0.5)
        {
          i = 2 + (y + 0.5 * x);

          printf("%d. i = %0.2f,\t x = %0.2f,\t y = %d\n", count++,i, x, y);
        }
    }

    return 0;
}

Output:

1. i = 5.75,     x = 5.50,       y = 1
2. i = 6.00,     x = 6.00,       y = 1
3. i = 6.25,     x = 6.50,       y = 1
4. i = 6.50,     x = 7.00,       y = 1
5. i = 6.75,     x = 7.50,       y = 1
6. i = 7.00,     x = 8.00,       y = 1
7. i = 7.25,     x = 8.50,       y = 1
8. i = 7.50,     x = 9.00,       y = 1
9. i = 7.75,     x = 9.50,       y = 1
10. i = 8.00,    x = 10.00,      y = 1
11. i = 8.25,    x = 10.50,      y = 1
12. i = 8.50,    x = 11.00,      y = 1
13. i = 8.75,    x = 11.50,      y = 1
14. i = 9.00,    x = 12.00,      y = 1
15. i = 9.25,    x = 12.50,      y = 1
16. i = 6.75,    x = 5.50,       y = 2
17. i = 7.00,    x = 6.00,       y = 2
18. i = 7.25,    x = 6.50,       y = 2
19. i = 7.50,    x = 7.00,       y = 2
20. i = 7.75,    x = 7.50,       y = 2
21. i = 8.00,    x = 8.00,       y = 2
22. i = 8.25,    x = 8.50,       y = 2
23. i = 8.50,    x = 9.00,       y = 2
24. i = 8.75,    x = 9.50,       y = 2
25. i = 9.00,    x = 10.00,      y = 2
26. i = 9.25,    x = 10.50,      y = 2
27. i = 9.50,    x = 11.00,      y = 2
28. i = 9.75,    x = 11.50,      y = 2
29. i = 10.00,   x = 12.00,      y = 2
30. i = 10.25,   x = 12.50,      y = 2
31. i = 7.75,    x = 5.50,       y = 3
32. i = 8.00,    x = 6.00,       y = 3
33. i = 8.25,    x = 6.50,       y = 3
34. i = 8.50,    x = 7.00,       y = 3
35. i = 8.75,    x = 7.50,       y = 3
36. i = 9.00,    x = 8.00,       y = 3
37. i = 9.25,    x = 8.50,       y = 3
38. i = 9.50,    x = 9.00,       y = 3
39. i = 9.75,    x = 9.50,       y = 3
40. i = 10.00,   x = 10.00,      y = 3
41. i = 10.25,   x = 10.50,      y = 3
42. i = 10.50,   x = 11.00,      y = 3
43. i = 10.75,   x = 11.50,      y = 3
44. i = 11.00,   x = 12.00,      y = 3
45. i = 11.25,   x = 12.50,      y = 3
46. i = 8.75,    x = 5.50,       y = 4
47. i = 9.00,    x = 6.00,       y = 4
48. i = 9.25,    x = 6.50,       y = 4
49. i = 9.50,    x = 7.00,       y = 4
50. i = 9.75,    x = 7.50,       y = 4
51. i = 10.00,   x = 8.00,       y = 4
52. i = 10.25,   x = 8.50,       y = 4
53. i = 10.50,   x = 9.00,       y = 4
54. i = 10.75,   x = 9.50,       y = 4
55. i = 11.00,   x = 10.00,      y = 4
56. i = 11.25,   x = 10.50,      y = 4
57. i = 11.50,   x = 11.00,      y = 4
58. i = 11.75,   x = 11.50,      y = 4
59. i = 12.00,   x = 12.00,      y = 4
60. i = 12.25,   x = 12.50,      y = 4
61. i = 9.75,    x = 5.50,       y = 5
62. i = 10.00,   x = 6.00,       y = 5
63. i = 10.25,   x = 6.50,       y = 5
64. i = 10.50,   x = 7.00,       y = 5
65. i = 10.75,   x = 7.50,       y = 5
66. i = 11.00,   x = 8.00,       y = 5
67. i = 11.25,   x = 8.50,       y = 5
68. i = 11.50,   x = 9.00,       y = 5
69. i = 11.75,   x = 9.50,       y = 5
70. i = 12.00,   x = 10.00,      y = 5
71. i = 12.25,   x = 10.50,      y = 5
72. i = 12.50,   x = 11.00,      y = 5
73. i = 12.75,   x = 11.50,      y = 5
74. i = 13.00,   x = 12.00,      y = 5
75. i = 13.25,   x = 12.50,      y = 5
76. i = 10.75,   x = 5.50,       y = 6
77. i = 11.00,   x = 6.00,       y = 6
78. i = 11.25,   x = 6.50,       y = 6
79. i = 11.50,   x = 7.00,       y = 6
80. i = 11.75,   x = 7.50,       y = 6
81. i = 12.00,   x = 8.00,       y = 6
82. i = 12.25,   x = 8.50,       y = 6
83. i = 12.50,   x = 9.00,       y = 6
84. i = 12.75,   x = 9.50,       y = 6
85. i = 13.00,   x = 10.00,      y = 6
86. i = 13.25,   x = 10.50,      y = 6
87. i = 13.50,   x = 11.00,      y = 6
88. i = 13.75,   x = 11.50,      y = 6
89. i = 14.00,   x = 12.00,      y = 6
90. i = 14.25,   x = 12.50,      y = 6

Note: Inner for loop executes from 5.5 to 12.5 with a 0.5 step increment for each loop. So its 15 iterations. Outer for loop executes 6 times. So total iterations equals 15 x 6 = 90 times. So 90 values will be printed to the console window.

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert

C Program To Generate Fibonacci Series using For Loop

Lets write a C program to generate Fibonacci Series, using for loop.

First Thing First: What Is Fibonacci Series ?
Fibonacci Series is a series of numbers where the first two Fibonacci numbers are 0 and 1, and each subsequent number is the sum of the previous two. Its recurrence relation is given by F_n = F_n-1 + F_n-2.

Below are a series of Fibonacci numbers(10 numbers):
0
1
1
2
3
5
8
13
21
34

How Its Formed:
0 <– First Number (n1)
1 <– Second Number (n2)
1 <– = 1 + 0
2 <– = 1 + 1
3 <– = 2 + 1
5 <– = 3 + 2
8 <– = 5 + 3
13 <– = 8 + 5
21 <– = 13 + 8
34 <– = 21 + 13

Video Tutorial: C Program To Generate Fibonacci Series using For Loop

[youtube https://www.youtube.com/watch?v=8VJVcwuYDPw]

YouTube Link: https://www.youtube.com/watch?v=8VJVcwuYDPw [Watch the Video In Full Screen.]

Source Code: C Program To Generate Fibonacci Series using For Loop

#include<stdio.h>

int main()
{
    int n1 = 0, n2 = 1, n3, count, num;

    printf("Enter the number of terms to be printed\n");
    scanf("%d", &num);

    printf("\n%d\n%d\n", n1, n2);

    for(count = 3; count <= num; count++)
    {
        n3 = n1 + n2;
        printf("%d\n", n3);

        n1 = n2;
        n2 = n3;
    }

    return 0;
}

Output:
Enter the number of terms to be printed
10

0
1
1
2
3
5
8
13
21
34

Logic To Generate Fibonacci Series using For Loop

We know that the first 2 digits in Fibonacci series are 0 and 1. So we directly initialize n1 and n2 to 0 and 1 respectively and print that out before getting into For loop logic. Since we’ve already printed two Fibonacci numbers, we assign 3 to loop control variable count and iterate through the for loop till count is less than or equal to the user entered number.

Inside For loop
As per definition of Fibonacci series: “..each subsequent number is the sum of the previous two.” So we add n1 and n2 and assign the result to n3 and display the value of n3 to the console.

Next, we step forward to get next Fibonacci number in the series, so we step forward by assigning n2 value to n1 and n3 value to n2.

For loop keeps repeating above steps until the count is less than or equal to the user entered number. If the user entered limit/count is 10, then the loop executes 8 times(as we already printed the first two numbers in the Fibonacci series, that is, 0 and 1).

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

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C Program To Print Multiplication Table Using For Loop

Lets write a C program to print the multiplication table of the number entered by the user. The table should get displayed in the following form:

Example: Multiplication table of 29
29 x 1 = 29
29 x 2 = 58
29 x 3 = 87
29 x 4 = 116
29 x 5 = 145
29 x 6 = 174
29 x 7 = 203
29 x 8 = 232
29 x 9 = 261
29 x 10 = 290

Simple Mathematical Trick — logical thinking

C Program To Print Multiplication Table Using For Loop

[youtube https://www.youtube.com/watch?v=fjEYZStx5_I]

YouTube Link: https://www.youtube.com/watch?v=fjEYZStx5_I [Watch the Video In Full Screen.]

Source Code: C Program To Print Multiplication Table Using For Loop

 
#include<stdio.h>

int main()
{
    int num, count;

    printf("Enter a number\n");
    scanf("%d", &num);

    printf("Multiplication table for %d is:\n", num);

    for(count = 1; count <= 10; count++)
    {
        printf("%d x %d = %d\n", num, count, (num*count));
    }

    return 0;
}

Output 1:
Enter a number
5
Multiplication table for 5 is:
5 x 1 = 5
5 x 2 = 10
5 x 3 = 15
5 x 4 = 20
5 x 5 = 25
5 x 6 = 30
5 x 7 = 35
5 x 8 = 40
5 x 9 = 45
5 x 10 = 50

Output 2:
Enter a number
10
Multiplication table for 10 is:
10 x 1 = 10
10 x 2 = 20
10 x 3 = 30
10 x 4 = 40
10 x 5 = 50
10 x 6 = 60
10 x 7 = 70
10 x 8 = 80
10 x 9 = 90
10 x 10 = 100

Output 3:
Enter a number
7
Multiplication table for 7 is:
7 x 1 = 7
7 x 2 = 14
7 x 3 = 21
7 x 4 = 28
7 x 5 = 35
7 x 6 = 42
7 x 7 = 49
7 x 8 = 56
7 x 9 = 63
7 x 10 = 70

Output 4:
Enter a number
6
Multiplication table for 6 is:
6 x 1 = 6
6 x 2 = 12
6 x 3 = 18
6 x 4 = 24
6 x 5 = 30
6 x 6 = 36
6 x 7 = 42
6 x 8 = 48
6 x 9 = 54
6 x 10 = 60

Logic: Multiplication Table

We ask the user to enter a number. We initialize for loop counter to 1 and iterate through the loop until loop counter is less than or equal to 10. Inside for loop we multiply the user entered number with the loop counter variable to get the result of multiplication table.

You can also watch C Program To Print Multiplication Table Using While Loop video tutorial.

For list of all c programming interviews / viva question and answers visit: C Programming Interview / Viva Q&A List

For full C programming language free video tutorial list visit:C Programming: Beginner To Advance To Expert