When interest compounds q times per year at an annual rate of r % for n years, the principal p compounds to an amount a as per the following formula:
a = p (1 + r / q) nq
Write a C Program to read 10 sets of p, r, n & q and calculate the corresponding a‘s.
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We ask the user to enter values for floating point variables p, n, r and q. We use the formula:
a = p (1 + r / q) nq
And display the result to the console window.
where,
p – principal amount;
n – number of years.
r – rate of interest;
q – number of times interest compounds per year.
Note: We need to convert the user entered interest into percentage by dividing the integer number by 100.
#include<stdio.h> #include<math.h> int main() { float p, n, r, q, a; int count; for(count = 1; count <= 10; count++) { printf("Enter principal amount\n"); scanf("%f", &p); printf("Enter number of years\n"); scanf("%f", &n); printf("Enter rate of interest\n"); scanf("%f", &r); r = r / 100; printf("Enter no of times you compound per year\n"); scanf("%f", &q); a = p * pow( (1 + (r/q)), n * q ); printf("Compounded amount is %f\n\n", a); } return 0; }
Output
Enter principal amount
5000
Enter number of years
2
Enter rate of interest
8
Enter no of times you compound per year
4
Compounded amount is 5858.296875
Enter principal amount
1000
Enter number of years
7
Enter rate of interest
5
Enter no of times you compound per year
1
Compounded amount is 1407.100464
Enter principal amount
2000
Enter number of years
5
Enter rate of interest
12
Enter no of times you compound per year
12
Compounded amount is 3633.393311
Enter principal amount
5000
Enter number of years
5
Enter rate of interest
5
Enter no of times you compound per year
5
Compounded amount is 6412.160156
Enter principal amount
Note: Above program keeps on iterating 10 times and asks the input 10 times.
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