Any year is entered through the keyboard, write a C program to determine whether the year is a leap year or not. Use the logical operators && and ||.
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Page Contents
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Leap Year Logic
1. If a year is a century year(year ending with 00) and if it’s perfectly divisible by 400, then it’s a leap year.
2. If the given year is not a century year and it’s perfectly divisible by 4, then it’s a leap year.
Century year is determined by modulo division of the entered year by 100. Example: year%100 == 0. If its century year, it must also be perfectly divisible by 400. i.e., year%400 == 0
(year%100 == 0 && year%400 == 0)
If the year is not century year, then it must be perfectly divisible by 4, for the year to be a leap year.
(year%100 != 0 && year%4 == 0)
Expected Output for the Input
User Input:
Enter a year
2024
Output:
2024 is a leap year
Video Tutorial: C Program To Determine Leap Year or Not using Logical Operators
[youtube https://www.youtube.com/watch?v=8IQcK85dNrw]
Source Code: C Program To Determine Leap Year or Not using Logical Operators
#include < stdio.h > int main() { int year; printf("Enter a year\n"); scanf("%d", &year); if( (year%100 == 0 && year%400 == 0) || (year%100 != 0 && year%4 == 0) ) { printf("%d is a leap year\n", year); } else { printf("%d is not a leap year\n", year); } return 0; }
Output 1:
Enter a year
2020
2020 is a leap year
Output 2:
Enter a year
2021
2021 is not a leap year
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