C Program to Generate Even Numbers Between Two Integers

C program to generate even numbers between 2 integer values input by the user.

Related Read:
Even or Odd Number: C Program
Even or Odd Number without using Modular Division: C Program

Note 1: An even number is an integer that is exactly divisible by 2.

Note 2: Even numbers are of the form 2 * n;

Note 3: Modular division( % ) returns remainder of division. For example, 10 / 2 = 5. But 10 % 2 = 0.

C Program to Generate Even Numbers Between Two Integers

 
#include<stdio.h>

int main()
{
    int count, limit;

    printf("Enter start value and end value to generate Even no's\n");
    scanf("%d%d", &count, &limit);

    printf("\nEven numbers between %d and %d are:\n", count, limit);

    while(count <= limit)
    {
        if(count % 2 == 0)
        {
            printf("%d\n", count);
        }
        count++;
    }

    return 0;
}

Output 1
Enter start value and end value to generate Even no’s
10
30

Even numbers between 10 and 30 are:
10
12
14
16
18
20
22
24
26
28
30

Output 2
Enter start value and end value to generate Even no’s
1
10

Even numbers between 1 and 10 are:
2
4
6
8
10

C Program to Generate Even Numbers Between Two Integers

In above c program, we ask the user to input 2 integer value and store it in variables count and limit. While loop keeps executing until the start value i.e., count is less than or equal to the end value i.e., limit.

Inside while loop, for every value of count, we check if its perfectly divisible by 2. If true, it’s a Even number and we output that number to the console window. On every iteration of the loop we increment the value of count by 1.

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Update:
In the above video I’ve said: “count should be exactly divisible by 0”.

I’m sorry about that. It should be – “Value inside variable count should be exactly divisible by 2.”