We ask the user to input 2 angles of the Triangle. And using C Program we calculate and output the 3rd angle.
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Triangle Valid or Not based On Sides: C Program.
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a + b + c = 180;
c = 180 – (a + b);
where a, b and c are angles of Triangle.
Note: Also not that if any of the angle is 0, then those 3 angles can’t form a Triangle, so it’s a invalid Triangle.
Find Missing Angle in a Triangle if two angles are given: C Program
#include < stdio.h > int main() { int a1, a2, a3; printf("Enter 2 angles of Triangle\n"); scanf("%d%d", &a1, &a2); a3 = 180 - ( a1 + a2 ); if(a1 != 0 && a2 != 0 && a3 != 0) { printf("The 3rd angle is %d\n", a3); } else { printf("Invalid angles of Triangle\n"); } return 0; }
Output 1:
Enter 2 angles of Triangle
0
90
Invalid angles of Triangle
Output 2:
Enter 2 angles of Triangle
90
90
Invalid angles of Triangle
Output 3:
Enter 2 angles of Triangle
90
80
The 3rd angle is 10
Output 3 outputs valid Triangle as addition of all 3 angles gives 180.
90 + 80 + 10 = 180.
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