Even or Odd Number using Ternary Operator and without using Modular Division: C Program

Today lets write a C program to check whether a user entered integer number is EVEN or ODD, without using modular division(%) operator and by using Ternary Operator / Conditional Operator.

Related Read:
Even or Odd Number without using Modular Division: C Program
Ternary Operator / Conditional Operator In C

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Even or Odd Number: Source Code

 
#include < stdio.h >

int main()
{
    int n;

    printf("Enter a integer number\n");
    scanf("%d", &n);

    ( (n/2)*2 == n ) ?
    (printf("%d is Even\n", n)) :
    (printf("%d is Odd\n", n));


    return 0;
}

Output 1:
Enter a integer number
10
10 is Even

Output 2:
Enter a integer number
5
5 is Odd

Even or Odd Number using Ternary Operator and without using Modular Division: C Program

Note: Division of an integer number by 2(which is also an integer number) always returns integer number.

Example 1:
If user enters n = 2;
Applying n = 2 to ( (n/2)*2 == n ).
( (2/2)*2 == 2 )
( (1)*2 == 2 )
( 2 == 2 ) // true

So user entered value, that is, 2 is even number.

Example 2:
If user enters n = 3;
Applying n = 3 to ( (n/2)*2 == n ).
( (3/2)*2 == 3 )
( (1)*2 == 3 )
( 2 == 3 ) // false

2 is not equal to 3. So user entered value, that is, 3 is odd number.
In above example, 3/2 gives back 1 and not 1.5 as 3 is divided by integer which returns only the integer part and discards the decimal part.

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