What to expect ?
Using PHP script insert user entered data/information into database and extract/fetch data stored in database and display it on the browser.
This video tutorial also teaches the MySQL queries.
In this video tutorial we have used a readymade form which uses POST method to pass the user entered information. To watch the coding/designing of this form go to POST Method In Action: Simple Form
MySQL Commands and Uses
mysql > drop database abc;
This command will delete the database by name abc, if its already present.
mysql > create database abc;
This MySQL command creates a new database by name abc.
mysql > use abc;
After creating the database abc, we must tell the console that we want to operate on the newly created database. i.e., use abc;
mysql > create table bbc(name varchar(15), company varchar(20));
This MySQL command is used to create a table by name bbc with two string type data fields name and company with character length of 15 and 20 respectively.
mysql > desc bbc;
This shows the description or the structure of the table.
mysql > select * from bbc;
This returns all the contents stored in the table bbc.
PHP Script
Connecting the PHP Script to database
<?php
$conn = mysql_connect("localhost","root","");
$db = mysql_select_db("abc",$conn);
?>
mysql_connect() is a standard function which takes 3 parameters. First parameter is host name, second parameter is the MySQL username, and the 3rd parameter is the MySQL password.
mysql_select_db() is also a php standard function. Firs parameter is the database name, with which you want the script to be connected to, and the second parameter is optional.
NOTE: We can put this database connection code inside a separate file and include it inside whichever script we want using include(); or include_once(); function. This way we can reduce the coding and this helps a lot while we are editing this information.
postform.php
<html> <head><title>POST Method in Action</title></head> <body> <form action="post.php" method="post"> Name <input type="text" name="user"><br /> Company<input type="text" name="comp"><br /> <input type="submit" value=" Submit Info"> </form> </body> </html>
This is a simple form which contains 2 input fields(user and comp) and a submit button. It uses POST method to pass the user submitted information/data.
post.php
<?php
$conn = mysql_connect("localhost","root","");
$db = mysql_select_db("abc",$conn);
?>
<?php
$name = $_POST['user'];
$company = $_POST['comp'];
# echo "My name is $name
And I'm the CEO of my company {$company}"
$sql = "INSERT into bbc values('$name','$company')";
$qury = mysql_query($sql);
if(!$qury)
echo mysql_error();
else
{
echo "Successfully Inserted";
echo "View Result";
}
?>
After storing the information passed by the user inside $name and $company variables, we use the MySQL query to store this data into the database.
$sql = "INSERT into bbc values('$name','$company')";
This MySQL query is stored into $sql variable and is passed to a standard PHP function for execution. i.e., mysql_query($sql);
Based on the result of the execution of the query, we show the proper messages using if statement.
mysql_error() is a standard PHP error function. This helps a lot in development stage, as it shows a descriptive error message. It is not advised to have this error function in the script at deployment stage.
show.php
If the query is executed successfully, a link to show.php file is shown and a “Successfully Inserted” message will be displayed on the browser.
<?php
$conn = mysql_connect("localhost","root","");
$db = mysql_select_db("abc",$conn);
?>
<?php
echo "<ul>";
$sql = "select * from bbc";
$qury = mysql_query($sql);
while($row = mysql_fetch_array($qury))
echo "<li>Name: $row[0]</li><li>Company: $row[1]</li>";
echo "</ul>";
?>
We have already explained the select query above.
$row = mysql_fetch_array($qury)
This PHP function gets all the result stored in $query and stores it inside $row variable in the form of an array.
If we put this above statement inside a While loop, the loop terminates once there are no more elements in the $query variable.
Now, echo/print the contents of the $row variable to get the contents being fetched by the database using SELECT query.
We can either use the indexing like: $row[0], $row[1] etc or we can directly mention the database field names to reduce confusion i.e., $row[name], $row[company] etc.
View Comments
hi satish, pls give me a reply to this problem??
How can we display image only using php code?? (with out html code)
okk ,, Satish ...your code is Awesome ....really nice...
i want to say about one problem ,,that is if i want to see all data in same page ..where i able to insert ..i want to say inserting and display would be same page ..how it possible..help please....
Thanks in Advance...
@Prasanna Look at this video tutorial Fetch/Extract Data From Database Without Refreshing Webpage: jQuery
jQuery will help you in your works. It'll take 24 to 48 hrs to learn it with our video tutorials.
All the best.
hii.. Satish....
your link is very much useful...i completely got you..
Thanks a lot...take care